An old man has Rs.(1! + 2! + ........ + 50!) ,all of which he wants to divide equally (without fractions) among his 'n' children. Then 'n' is equal to.....
a)5 b)7 c)9 d) 11

• Checked up to 9.
  Sum of (1! + 2! + ........ +8!) = 46233 which is divisible by 9.
  after that each term is also divisible by 9.
  
  so min n=9.
  
  I think 11 may also be possible but we have to check further.
• 12 years agoHelpfull: Yes(1) No(0)