Find three consecutive positive integers such that the square of their sum exceeds the sum of their squares by 214.

• 5,6,7
  if nos are x-1, x and x+1, then
  
  9x^2 = (x-1)^2 +x^2 +(x+1)^2 + 214
  6x^2=216
  x=6
  hence nos are 5,6,7
• 12 years agoHelpfull: Yes(1) No(1)
• three consecutive numbers are 5,6,7
• 8 years agoHelpfull: Yes(0) No(0)