Q3. Given 3 lines in the plane such that the points of intersection form a triangle with sides of length 20, 20 and 30, the number of points equidistant from all the 3 lines is
a)1 b)3 c)4 d)0

• answer is 4......
  there will be three circle which can drawn outside the circle taking the sides of the triangle extended as tangents.
  hence total points will be 1+3= 4 points.
  
• 13 years agoHelpfull: Yes(8) No(1)
• 4
  one point ie incenter of triangle
  other thee point is obtained by xcenter i.e. by angle bisector of exterior angle of three side
  hence 1+3=4
• 13 years agoHelpfull: Yes(7) No(1)
• ans is 1 as in a equilateral triangle centroid and orthogonal centroid both are same point
• 13 years agoHelpfull: Yes(4) No(5)
• 1
• 13 years agoHelpfull: Yes(2) No(4)
• 1
• 13 years agoHelpfull: Yes(2) No(4)
• 1
• 13 years agoHelpfull: Yes(2) No(4)
• 1
• 13 years agoHelpfull: Yes(2) No(3)