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Maths Puzzle
Find a geometric series which has a third term of 7/4 and a sum to infinity of 14.
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- series is 7,7/2,7/4,7/8,7/16....
a/(1-r) =14
a=14-14r
third term =ar^2 = (14-14r)*r^2= 14*(1-r)*r^2 =7/4
(1-r)*r^2 = 1/8 = (1/2)*(1/4)
so r=1/2 , a= 7
series is 7,7/2,7/4,7/8,7/16.... - 12 years agoHelpfull: Yes(1) No(0)
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