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You have two jars, 50 red marbles and 50 blue marbles. A jar will be picked at random, and then a marble will be picked from the jar. Placing all of the marbles in the jars, how can you maximize the chances of a red marble being picked? What are the exact odds of getting a red marble using your scheme?
Read Solution (Total 4)
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- one red ball in one jar. 49 red + 50 blue in second jar.
probability to get red ball is 1/2(1+49/99) = 74/99 - 14 years agoHelpfull: Yes(15) No(0)
- 1/2(1+49/99)
as by putiing one red ball in one jar and remaining ball in other jar we get the max prob=
74/99 - 14 years agoHelpfull: Yes(7) No(2)
- keeping 25 blue , 25 red marbles in each jar .... odds of getting is 1:1
- 14 years agoHelpfull: Yes(1) No(11)
- 1/2
- 14 years agoHelpfull: Yes(1) No(12)
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