CAT
Exam
When the smallest three-digit number which when divided by 7, 8 and 11 leaves respective remainders of 4, 3 and 7, is divided by 9, the remainder is
Read Solution (Total 2)
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- remainder is 7.
number is 403.
403/9 will give 44 as quotient and 7 as remainder - 12 years agoHelpfull: Yes(6) No(5)
- 403 is the smallest three digit number which when divided by 7, 8 and 11 leaves respective remainders of 4, 3 and 7.
403/9 = Remainder : 4
403 is divided by 9, remainder is 4 (399+4)
403 is divided by 7, remainder is 4 (399+4)
403 is divided by 8, remainder is 3 (400+3)
403 is divided by 11, remainder is 7 (396+7)
- 12 years agoHelpfull: Yes(1) No(6)
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