Orkut
Maths Puzzle
Q. A,B and C buy a box of chocolates each. Mr.A distributes the chocolates in his box equally among his 6 children, Mr.B among his 7 children and Mr.C among his 8 children. Then they pool their respective remaining number of chocolates and find that they could distribute these equally among themselves or equally among themselves when a fourth friend D joins them. Which of the following can be the total amount that the three friends spent on the chocolates if each chocolate costs exactly Rs. 2.50 (Assume that the only cost of a box of chocolates is that of the chocolates in it)
Option
a) 210
b) 120
c) 150
d) 180
Read Solution (Total 1)
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- Rs 150.
Together they bought 60 choclates and each bought 20 choclates.
Remaining choc after distributing among 6,7,8 children respectively by each one = 2+6+4= 12 choc. which is eqaully divisible among 3 or 4 friends. - 12 years agoHelpfull: Yes(3) No(1)
Orkut Other Question
Q. In a game, the 1st person tosses a coin. If the outcome is head, he throws a dice and the result is recorded as his score and he gets one more chance to toss the coin. If the outcome is tail then the next person gets a chance to toss the coin. What is the probability that a person scores 35 points after 6 tosses in this game?
Option
a) (1/32)(1/6)^5
b) (1/32)(1/6)^6
c) (1/64) (1/6)^6
d) (1/64) (1/6)^5
Q. You are playing a game with your friend. Your friend chooses three of the numbers among (1, 2, 3, 4, 5, 6, 7, 8, 9). You will call four numbers in each turn, and he will tell you how many of them are among the chosen numbers.
In order to guarantee to find these numbers in all cases, how many turns are needed?