Number of Odd divisor of 9 000 000 a 21 b 73 c 74

9,000,000=2^6*3^2*5^6
so No of odd divisors=
for 2= 2^0
for 5= 5^0,5^1,5^2,5^3,5^4,5^5,5^6
for 3=3^0,3^1,3^2

so No of divisors=1*7*3
=21 Ans...
10 years agoHelpfull: Yes(7) No(0)
ans is 21 , same was asked in october 28.
10 years agoHelpfull: Yes(4) No(0)
9,000,000=9*1,000,000
=3*3*10*10*10*10*10*10
odd number=3*3*5*5*5*5*5*5
so 2+6+6+6+1=21
9 years agoHelpfull: Yes(3) No(2)
9000000=2^6*3^2*5^6
we find odd diviser then evem power is =1
2^0*(2+1)*(6+1)=21
9 years agoHelpfull: Yes(0) No(0)
9000000=3^2*10^6=3^2*2^6*5^6
odd divisors=(2+1)(0+1)(6+1) we will get odd divisors when power of 2 should be zero.
so, 3*1*7=21
8 years agoHelpfull: Yes(0) No(0)
answer (a) is the correct answer
the factor of the 9,000,000 is =3^2 * 2^6 * 5^6
so total no of the factor is =(2+1)(6+1)(6+1)=147
so total no of even factor is =(2)(6+1)(6+1)=126
so total no of odd factor is =total factor-even factor
=147-126
=21
7 years agoHelpfull: Yes(0) No(0)

Number of Odd divisor of 9,000,000
a) 21 b) 73 c )74