An amount of money is to be distributed among A, B and C in the ratio of 6:19:7 respectively. If C gives Rs. 200/- of his share to B, the ratio among A, B and C becomes 3:10:3 respectively .What was the total amount?

• An amount of money is to be distributed among A, B and C in the ratio of 6:19:7 respectively.
  
  Let amounts are 6x, 19 x and 7x respectively.
  
  As per given condition
  
  6x:19x+200: 7x-200 :: 3:10:3
  
  it means
  
  6x= 7x-200
  x=200
  
  Then amounts are 1200,3800,1400,
  Total amount = 1200+3800+1400= Rs. 6400
  Also total amt = 200*(6+19+7)=200*32= Rs 6400
• 12 years agoHelpfull: Yes(4) No(1)
• agree with AMAN's ans...
• 12 years agoHelpfull: Yes(0) No(0)
• A:B:C 6:19:7
  x is the total amt.
  A=6/32x,B=19/32x,c=7/32x
  
  the diffrence in ratio, by C gives 200 of his share to B 7 to 3 out of total total 16
  ie, 7/32x-3/16x=200
  1/32x=200
  ie, x=6400
• 12 years agoHelpfull: Yes(0) No(0)