If 830 is divided into three parts such that 4 times the first part is equal to 5 times the second and 7 times the third, then the first part is?

• 350
  Let the parts are X, Y and Z
  as per the question,
  4X=5Y=7Z=k (assume 4x,5y,7z is equal to k, where k is a constant)
  Now X=k/4
  Y=k/5
  Z=k/7
  since X+Y+Z=830
  therefore k/4+k/5+k/7=830
  k=1400
  Now X=1400/4=350
  
• 12 years agoHelpfull: Yes(31) No(0)
• Rs 350
  
  If x,y,z are three parts, then
  4x=5y=7z= p (say)
  x=p/4
  y=p/5
  z=p/7
  as per condition
  x+y+z=830
  putting values of x,y,z and solving for p, we get
  p=1400
  x=350,y=280,z=200
• 12 years agoHelpfull: Yes(7) No(2)
• 830. divided into 3 parts A, B, C.
  Acc to question.. B=4A/5 and C=4A/7 also.. A+B+C=830 (eq 1).
  put value of B and C in eq 1. answer is A=350.
  
• 12 years agoHelpfull: Yes(3) No(0)
• 4A=5B=7C
  A/4=B/5=C/7
  a:b:c=35:28:20
  83-830
  35-?
  answer is 350
• 7 years agoHelpfull: Yes(1) No(0)
• Since 4x=5y=7z
  Simply put values of y and z in eq. x+y+z=830
  Ans. will be 30.
• 12 years agoHelpfull: Yes(0) No(14)
• Since 4x=5y=7z
  Simply put values of y and z in eq. x+y+z=830
  Ans. will be 350.
• 12 years agoHelpfull: Yes(0) No(0)