4,7,12,21,38,__,__

• Missing Number = 71, 136
  
  Final Series : 4,7,12,21,38,71,136
  
  @@
  4,7,12,21,38.
  Difference of series is
  3,5,9,17
  Again we take difference
  2,4,8.
  
  So, series will be 4,7,12,21,38,71,136
  
  Taking difference, we get = 3,5,9,17,33,65
  
  Again taking difference, get = 2,4,8,16,32.
  
  Solved.
• 12 years agoHelpfull: Yes(5) No(3)
• Missing numbers are 71 and 136
  The given series is like as
  4*1-0=4
  4*2-1=7
  7*2-2=12
  12*2-3=21
  21*2-4=38
  so
  38*2-5=71
  71*2-6=136
  
• 12 years agoHelpfull: Yes(3) No(1)
• 71,136
  since the initial difference sequence 3,5,9,17,33,65
  again we have 2,4,8,16,32 compute backward we get 71,136
• 12 years agoHelpfull: Yes(0) No(1)
• 62 bngh,l
• 12 years agoHelpfull: Yes(0) No(1)
• 4*2=8-1=7
  7*2=14-2=12
  12*2=24-3=21
  21*2=42-4=338
  38*2=76-5=71
  71*2=142-6=136
• 6 years agoHelpfull: Yes(0) No(0)