If sum of the four numbers is 64.If 3 is added to first number, 3 is subtracted from second number, the third is multiplied by 3 and the fourth is divided by 3, then all the results are equal.What is the difference between largest and smallest of the original number?

• 32 is the difference between largest and smallest of the original number.
  
  First Number = 9
  Second Number= 15
  Third Number = 4
  Fourth Number= 36
  
  Sum of four numbers = 9+15+4+36 = 64
  
  Conditions:
  
  First Number = 9 + 3 =12
  Second Number= 15- 3 =12
  Third Number = 4 * 3 =12
  Fourth Number= 36/ 3 =12
  
  All the result are equal to 12. Hence it is proved.
  
  Largest Number = 36
  Smallest Number= 4
  Difference between these two = 36 - 4 = 32 :)
• 12 years agoHelpfull: Yes(12) No(2)
• 32
  let a,b,c,d be the numbers
  let a+3=b-3=c*3=d/3=k
  then a=k-3,b=k+3,c=k/3,d=3k
  a+b+c+d=64
  k=12
• 12 years agoHelpfull: Yes(5) No(2)
• a+b+c+d=64
  a+3=b-3=c*3=d/3
  solving these will get
  a=9
  b=15
  c= 4
  d= 36
  diff = 36-4 =32
• 12 years agoHelpfull: Yes(3) No(0)
• difference between largest and smallest of the original number = 32
  The numbers are 9,15,4,36 as
  9+3=12
  15-3=12
  4*3=12
  36/3=12
  
• 12 years agoHelpfull: Yes(0) No(0)