The sum of the areas of two squares is 640 meter sq. If the difference in their perimeters be 64 m,find the sides of the two squares

• The sides of two squares is 24 meters and 8 meters.
  area of square of 24 meters side = 576 sq. meter
  area of square of 8 meters side = 64 sq. meter
  The sum of the areas of two squares is = 576 + 64 = 640 meter sq
  the difference in their perimeters = 96 - 32 = 64 meters
  
  
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