1 3th of the passengers got down at first stop and 30 people got into the bus 1 4th of

Let initial capacity be x
In first stop x/3 got out
Therefore remaining Passengers are(x-x/3)
now remaining passengers are(x-x/3+30)=(2x+90)/3

Now in second stop 1/4th got out i.e.,
1/4(2x+90/3)
remaining=2x+90/3-2x+90/12=2x+90/4

in third stop 84 got out i.e.,
2x+90/4 - 84=0
and by solving we get x=123
Therefore initial capacity of passengers was 123
12 years agoHelpfull: Yes(5) No(20)
99 is the right answer
let x in the no of passengers
at 1 stop (x-x/3)+30=(2x/3)+30
at 2 stop it is 3/4(2x/3)+30)+12
at last stop no of passengers left is 84
so eqn will be as 3/4(2x/3)+30)+12=84
so by solving above equation x is 99
so initial capacity of the bus is 99 passengers
12 years agoHelpfull: Yes(2) No(0)
let x be the no of initial passengers
no of passengers left in 1st stop (2x/3)+30
no of passengers in the 2nd stop is (1/4((2x+90)/3))+12
is equal to 84 so eqn is (2x+90)/12=72
so x=387ans.....
12 years agoHelpfull: Yes(1) No(6)
3/4(2x/3+30)+12=84 ==> x = 99
12 years agoHelpfull: Yes(1) No(0)
First Solution Answering 99 is correct from every aspect...Rest of the solutions have interpreted question in different manner n some of them have calculation mistakes...99 is correct answer..
12 years agoHelpfull: Yes(0) No(0)

1/3th of the passengers got down at first stop and 30 people got into the bus, 1/4th of the passengers got down at second stop and 12 people got into the bus.In last stop 84 people got down from the bus. What is the initial capacity of the bus?