If the difference of squares of two numbers is 88 and if the larger number is 5 less than twice the smaller number, Find the two numbers.

• 9 and 13 are the two numbers.
  
  Let X = Larger number
  And Y = Smallest number
  
  So,
  X^2 - Y^2 = 88-------->(i)
  X = 2Y - 5 ---------->(ii)
  
  Substitute equation (ii) in (i)
  
  (2Y-5)^2 - Y^2 = 88
  4Y^2 - 20Y + 25 - Y^2 = 88
  3Y^2 - 20Y - 63 = 0
  
  Equation can be written as
  3Y^2 - 27y + 7y - 63 = 0
  3Y(Y-9) + 7(Y-9) = 0
  (3Y+7) (Y-9) = 0
  3Y+7=0 (or) Y-9=0
  Y = -7/3 (or) Y=9
  Y = 9
  So,
  X = 2Y-5
  X = 2(9)-5
  X = 13.
  
  X = 13 = Larger number
  Y = 9 = Smallest number
• 12 years agoHelpfull: Yes(5) No(0)