there are two boxex, one containing 39 red balls and other 29 green balls. yao are allowed to move the balls betn the booxes so that you choose a box randomly and a ball at random from the choosen box, the probability of getting a red ball is maximized. the maximum probability is
a. .60
b. .50
c. .80
d. .30

• To maximise the probability of red balls, you need to keep 1 red ball in 1 box and transfer remaining to the other. So box1= 1red ball, box2 = 29 green+38 red. So first to select box1, probability is 1/2.Now only 1 red ball is there, so prbability for red is 1. Total probability is (1/2)*1.Similarly probability of red ball in box2= (1/2)(38/67). total probability = (1/2)*1 + (1/2)(38/67)~ 0.8
• 13 years agoHelpfull: Yes(32) No(0)
• Keep one red ball in one box and put 38 red balls and 29 green balls in other box.
  
  Then probability of getting red ball = 1/2 *1 + 1/2 * 38/67 = 105/134 = 0.7835
• 13 years agoHelpfull: Yes(6) No(0)
• the ball may b redor blue.
  the max probability is 1/2+1/2*(38/67)=.60
• 13 years agoHelpfull: Yes(0) No(4)
• (1/2)*(1)+(1/2)*(38/67)=.79=.8
  C) .8
• 13 years agoHelpfull: Yes(0) No(3)
• atleast one red ball should be picked.
  so probability to take a red ball from a box is (1/2)*1
  red balls in second box is(1/2)*(38/67)
  sol:(1/2)+(1/2)*(38/67)
  so probability is 0.7835=0.80
• 11 years agoHelpfull: Yes(0) No(0)