If two articles are bought for Rs.600 and one of them sold at a profit of 22% and the other at a loss of 8% then no profit or loss is made. What is the selling price of the article that sold at a loss?

• Selling price of the article that sold at a loss = 404.80
  
  Let X = Price of the first article
  And Y = Price of the second article.
  
  Therefore, X+Y = 600
  
  1st article be sold at a profit of = 22%,
  Therefore, selling price of the first article = X + (22/100)X = 1.22X
  
  while the 2nd one be sold at a loss of = 8%.
  Therefore, selling price of the second article = Y - (8/100)Y = 0.92Y
  
  Total selling price of the first and second article = 1.22X + 0.92Y
  
  No profit or loss in transaction.
  So, Selling price is equal to Cost price of both articles.
  
  So, 1.22X + 0.92Y = X+Y = 600------->(i)
  
  As X+ Y = 600 --> Y = 600 - X.
  
  Substituting Y value in eqn (i), we get
  
  1.22X + 0.92(600 - X) = 600
  
  --> 1.22X - 0.92X = 600 - 0.92*600
  --> 0.3X = 0.08*600 = 48
  --> X = 48/(0.3)
  --> X = 160
  
  If X = 160, then Y=600-160 --> Y = 440.
  
  The selling price of article 2(loss) = 0.92 *Y
  = 0.92 *440
  = 404.80
• 12 years agoHelpfull: Yes(7) No(0)
• Let X = Price of the first article
  And Y = Price of the second article.
  X+Y=600
  1st article sold at 22% profit..
  if X is the cost price then selling price=122X/100.
  2nd article old at 8% loss.
  if Y is the cost price then selling price=92Y/100.
  (122X/100)+(92Y/100)=600..............(i)
  X+Y=600............................(ii)
  by solving (i) and (ii) we get
  X=160,Y=440(ans)
• 12 years agoHelpfull: Yes(0) No(4)