Complete the series
8,11,16,22,32,__,__

• Another Possibility.
  Missing numbers = 33, 64
  
  Final series : 8,11,16,22,32,33,64
  
  It have two sequence.
  1st sequence : 8, 16, 32, ??
  2nd sequence : 11, 22, ??
  
  1st sequence as,
  
  8
  8*2 = 16
  16*2 = 32
  32*2 = 64
  
  2nd sequence as,
  11*1 =11
  11*2 =22
  11*3 =33
• 12 years agoHelpfull: Yes(5) No(2)
• Missing numbers = 44,64
  
  Final Series : 8,11,16,22,32,44,64
  It have two sequence.
  
  1st sequence : 8, 16, 32, ??
  2nd sequence : 11, 22, ??
  
  1st sequence as,
  
  8
  8*2 = 16
  16*2 = 32
  32*2 = 64
  
  2nd sequence as,
  11
  11*2 =22
  22*2 =44
• 12 years agoHelpfull: Yes(4) No(1)
• This series is a combination of two patterns.
  1st pattern is 8, 16, 32, ... in which number is doubled again and again.
  2nd pattern is 11, 22, ... in which number is doubled again and again.
  Therefore, 44 and 64 will come after 32.
• 12 years agoHelpfull: Yes(1) No(0)
• 8,11,16,22,32....
  (11-8),(16-11),(22-16),(32-22)..
  =3,5,6,10.....
  =3,5,(3*2),(5*2),(6*2),(10*2)...
  =3,5,6,10,12,20...
• 12 years agoHelpfull: Yes(0) No(3)
• the difference between consecutive no.s:3,5,6,10 =3,5,(3*2),(5*2)
  
  so next numbers will be 32+(3*3),((32+(3*3))+(5*3))=41,56
  
  so the final series:8,11,16,22,32,41,56
• 12 years agoHelpfull: Yes(0) No(0)