An aircraft takes of from A(89 degree N,10 deg E)at 6.00am local time to B(50 deg S,70 deg W).If the flying time is 10 hours,then what is the local time at B?

• 1 degree=4 minutes
  since local time difference depends on longitude only, total degrees travelled=10 deg E+70 deg W=80 deg
  total time difference=80*4=320 minutes=5 hours 20 minutes
  time of journey=10 hours
  local time at A 6 am + 10 hrs - time diff (aircraft is travelling west)
  local time at B=10.40am
• 14 years agoHelpfull: Yes(10) No(2)
• 1 degree=4 minutes
  since local time difference depends on longitude only, total degrees travelled=10 deg E+70 deg W=80 deg
  total time difference=80*4=320 minutes=5 hours 20 minutes
  time of journey=10 hours
  total time=15 hrs 20 mins
  local time at B=9:20pm.
  
• 14 years agoHelpfull: Yes(8) No(3)
• avik ur answer is slightly wrong.as the aircraft is travelling from est to west the local time should be calculated by subtracting and not adding
• 14 years agoHelpfull: Yes(2) No(1)
• @chamar: no boss take into account the magnitude..my solution is 100% correct and verified by someone who is doing masters in Geography...so...
• 14 years agoHelpfull: Yes(2) No(2)