A runs 1 ¾ times as fast as B. if A gives B a start of 84 m, bow far must
winning post be so that A and B might reach it at the same time?

• if in the question that A runs 1 3/4 times i.e., 7/4
  then the solution will be as follows
  
  Ratio of the rates of A and B = 7/4 : 1 = 7 : 4.
  So, in a race of 7 m, A gains 3m over B.
  
  3 m are gained by A in a race of 7 m.
  
  84 m are gained by A in a race of (7/3 x 84) m = 196 m.
  
  Winning post must be 196 m away from the starting point.
  
• 12 years agoHelpfull: Yes(4) No(1)
• Good observation by Vignesh.
• 12 years agoHelpfull: Yes(1) No(0)