TCS
Company
how many 8 digit numbers can be formed from 1,2,3,4,5 with repetition which are divisible by 4
Read Solution (Total 2)
-
- last 2 digits can be 12,24,32,44,52
so 8 digit numbers that can be formed from 1,2,3,4,5 with repetition which are divisible by 4 = 5*5^6 = 5^7 = 625*125 = 78125 - 12 years agoHelpfull: Yes(12) No(1)
- solution:4*5^6
as per problem.........a number is divisible by 4 if it ends with...12,32,24,44
totaly 4
for remaining 6 places:5^6 numbers are formed.....
so answer is 4*5^6 - 12 years agoHelpfull: Yes(2) No(4)
TCS Other Question