Others Maths Puzzle

If the sum of 101 distinct terms in arithmetic progression is zero, in how many ways can three of these terms be selected such that their sum is zero ?

Read Solution (Total 1)

1250 ways are possible.

600 ways for 2 +ve terms and 1 -ve term.
600 ways for 2-ve terms and 1 +ve term.
1+ve term, 0 and one -ve term in 50 ways
Total ways =600*2+50 =1250 ways
12 years agoHelpfull: Yes(2) No(3)

Others Other Question

A,B,C,D each had some money.D doubled the amounts with the others.C then doubled the amounts with the others.B then doubled the amount with the others.A then doubled the amount with the others.At this stage,each of them had Rs 80.Find the initial amount with C.

A) 45
B) 65
C) 95
D) 85 A four digit number numbered from 0000 to 9999 is said to be lucky, if the sum of the first two digits is equal to the sum of the last two digits. Find how many such numbers are possible ?