The sum of x% of y and y% of z is z% of x. x and z are integers such that 1 =< x =< 9, 1 =< z =< 9. If y is a perfect square number then how many ordered pair (x, z) are possible satisfying the given condition.

OPTION 1) 1
2) 2
3) 3
4) 4
5) 5
6) 6
7) 7
8) 7
9) 9
10)0

• y=xz/(x+z) and y perfect square so only (2,2) and (8,8) full fill this equestion
• 9 years agoHelpfull: Yes(0) No(0)