The price of precious stone is directly proportional to square of its weight. what will be the loss incurred if a stone weighing 28gm and costing 28,000 breaks into two pieces whose weights are in the ratio 15:13?
(A)No loss (B)10,000 (C)28,000 (D)9,500 (E)14,000

• x=28000/28^2=35.71
  cost of 15g=35.71*15^2=8035.714
  cost of 13g=35.71*13^2=6035.714
  total cost=14071.428
  loss=28000-14071.428=13928.5=14000
• 13 years agoHelpfull: Yes(7) No(0)
• Ans (E) 14,000
  let the price be P and weight be W.
  thus P=kW*W where k= proportionality constant
  k= 28000/28*28= 35.7
  now, P1= (35.7)*13*13=6033
  P2= (35.7)*15*15= 8032
  thus, Loss= (P - (P1+P2))= 13934.5= aprox 14,000
• 13 years agoHelpfull: Yes(4) No(0)
• the answer is approx 14000.because 28^2=784.
  now we know the price is prop to square of wt.therefore 28000=k*784
  k=35.714.now the two wts can be calculated 15gm and 13gm.the net price becomes 15^2*35.71+13^2*35.71=14069.64.now 28000-14069.64=13930.26 which is approx 14000
• 13 years agoHelpfull: Yes(3) No(0)
• let price=p,weight=w
  p=k w^2 ---------eq(1) here k is a constant taken
  as it is given dat price is directly proportional to weight
  given w=28,p=28000
  so from eq(1),k=1000/28
  now the broken pieces r 15 nd 13gm
  by putting the values of w and k in eq(1) we get
  p1=8035.71(for w=15)
  p2=6035.71(for w=13)
  total cost for broken pieces=(8035.71+6035.71)=14071.42
  so the loss=(28000-14071.42)=13928.58
• 13 years agoHelpfull: Yes(3) No(0)
• say 28 isdivided into 15 n 13
  square both the number to bcm 225+169=394
  now squaring 28 we get 784
  so loss incurred 390 so ,fr 784 390 is the loss what willbe for 28000 i.e 14000
• 13 years agoHelpfull: Yes(3) No(0)
• Price is directly propotional to square of the weight
  So P=k*sq(w) where k=constant
  P=28000
  w=28gm
  k=1000/28
  Price of the ratio part
  P1=k(15*15)
  P2=k(13*13)
  P1+P2=14000
  loss incurred=28000-14000=14000
  ans is E
• 13 years agoHelpfull: Yes(3) No(0)