At 1 PM, Ship A leaves port heading due west at
x miles per hour. Two hours later, Ship Bis 100 miles due south of the same port and heading due north at y miles per hour. At 5PM, how far apart are the ships?

• At 5PM, ship A has travelled 4x miles to the West of the port and ship B has travelled 4y towards the port from South of it. So, ship B is now (100-4y) miles due South of the port.
  Hence, the distance between Ship A & B is square root of (100-4y)^2+(4x)^2.
• 12 years agoHelpfull: Yes(0) No(0)