The length of a rectangular field is six yards more than its width. If the area of the field is 40 sq. yards,
find its length and width

• length=10yards,breadth=4yards ans.
  sol:
  Let l and b are the length and breadth of the rectangular field
  then according to the problem,
  l=b+6---(i)
  we know that:
  area of rectangle=l*b
  ->l*b=40 sq.yards [from the question]
  ->(b+6)*b=40 ,using (i)
  therefore,b=-10,4 but breadth will not equal to -10
  so, b=4 & l=4+6=10
  hence,l(length)=10yards
  b(breadth)=4yards ans.
• 12 years agoHelpfull: Yes(2) No(0)
• l=w+6
  l*w=40
  (w+6)*w=40
  w^2+6w-40=0
  w^2+10w-4w-40=0
  w(w+10)-4(w+10)=0
  (w+10)(w-4)=0
  w=-10 or w=4
  width should be positive value so w=4
  l=w+6=4+6=10
  lenght=10 yards,width=4yards
• 12 years agoHelpfull: Yes(0) No(1)