TCS
Company
HR Interview
Interview
A dealer originally bought 100 identical batteries at a total cost of q rupees. If each battery was sold at 50 percent above the original cost per battery, then, in terms of q, for how many rupees was each battery sold?
Read Solution (Total 4)
-
- 3q/200 rupees was each battery sold.
Cost of 1 battery = q/100
Each battery sold with profit 50% = q/100 + q/100*50/100
=q/100+q/200
=3q/200
Eg: Cost of each battery = 1rs. It means q = 100 (100*1 = 100)
==> Each battery sold with profit 50% . Therefore 1 battery = 1.50rs
Now put q=100 in 3q/200:
3(100)/200
300/200 = 1.50rs(Each battery rate. proved) - 12 years agoHelpfull: Yes(11) No(2)
- cost per battery=q/100
50% increase in the price per battery=q/100+(q/100)*(50/100)=3q/200=0.015q rs. - 12 years agoHelpfull: Yes(4) No(6)
bought for q/100 dollars per battery ( as it is written there "originally" , tht means this amount doesnt include any profit of the dealer!)
each battery sold with profit 50% is
q/100 + q/100*50/100
=q/100+q/200
=3q/200
option A is correct- 12 years agoHelpfull: Yes(1) No(2)
- correct ans : 3q/200
Cost of 1 battery = q/100
Each battery sold with profit 50% = q/100 + q/100*50/100
=q/100+q/200
=3q/200
cost of 1 battery =3q/200
- 11 years agoHelpfull: Yes(1) No(0)
TCS Other Question