exam
Maths Puzzle
Numerical Ability
page 141 number 25
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I am comlpetley lost at how to begin to solve this problem
here is the question
4/3 = 8
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b
the way it is written in the book is 4/3 divided by b equals 8
Let f(x) = -x^3 + 3x^2 - 3x + 1, and g(x) be f(x) divided by 1 - x; solve for
g(x) if 1 -x is a factor or f(x).
a. g(x) = x^4 - 4x^3 + 6x^2 - 4x + 1
b. g(x) = x^3 - 3x^2 + 3x -1
c. g(x) = -x^2 + 2x - 1
d. g(x) = x^2 - 2x + 1