A is driving on a highway when the police fines him for over speeding and exceeding the limit by 10 km/hr. At the same time B is fined for over speeding by twice the amount by which A exceeded the limit. If he was driving at 35 km/hr what is the speed limit for the road?

• excess speed of A=10
  SPEED of B=35
  as fine of B is double to that of A, so excess speed of B=10*2=20
  hence speed limit=35-20=15
• 14 years agoHelpfull: Yes(20) No(2)
• let x be the speed limit
  a exceeded speed limit by 10
  so x+10
  b exceeded speed limit twice that of a
  so x+20
  for 35km/hr
  35=x+20
  x=35-20
  x=15
  so speed limit is 15km/hr
• 12 years agoHelpfull: Yes(12) No(0)
• 15 km/hr
• 14 years agoHelpfull: Yes(3) No(3)
• excess speed of A=10
  SPEED of B=35
  as fine of B is double to that of A, so excess speed of B=10*2=20
  hence speed limit=35-20=15
• 12 years agoHelpfull: Yes(2) No(2)
• ans 15km/hr.
  let the speed limit be x
  speed of A=x+10,Speed of B=x+20
  solving x=20=35 we get x=15
• 14 years agoHelpfull: Yes(0) No(1)
• The speed limit for road is 15Km/hr.
  Police fined certain amount to A for overspeeding by exceeding the limit by 10 km/hr while it fined B twice the amount by which it fined A. So B exceeded the limit by 20 Km/hr. As B was driving at the speed of 35 Km/hr, so the speed limit of road was 35-20 = 15 km/hr.
• 13 years agoHelpfull: Yes(0) No(0)
• B TRAVELING WITH 35KMPH
  =>A IS AT 17.5KMPH AND EXCEEDS BY 10KMPH.
  SO SPEED LIMIT=17.5-10=7.5KMPH
• 12 years agoHelpfull: Yes(0) No(5)