TCS
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Numerical Ability
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Five bells first begin to toll together and then at intervals of 3,5,7,8,10 seconds. Find after what interval they will again toll together. How many times do they toll together in one hour ???
Read Solution (Total 9)
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- LCM of 3,5,7,8,10 = 840 secs = 14 mins
After every 14 mins, the bells will toll together.
At begining of the hour, they toll together.
so the bells will toll together 1+4= 5 times in 1 hour. - 12 years agoHelpfull: Yes(17) No(0)
- LCM OF (3,5,7,8,10)=840 SEC = 14 MIN
FOR EVERY 14 MIN ALL BELLS TOLL TOGETHER
SO FOR 60 MIN = 4+1=5 TIMES - 12 years agoHelpfull: Yes(3) No(1)
- lcm=840secs=14 mins so 5 times in 1 hr
- 12 years agoHelpfull: Yes(2) No(0)
- lcm of 3,5,7,8 is 840...1hr=3600sec and 3600/840=4 considering integer...so 1+4=5 in total
- 12 years agoHelpfull: Yes(2) No(0)
- 14 min ,4 times
- 12 years agoHelpfull: Yes(1) No(3)
- LCM of(3,5,7,8,10)=804=14min
every 14 min after all rang together
so in one hour 60/14=4+1=5 - 12 years agoHelpfull: Yes(1) No(1)
- LCM of(3,5,7,8,10)=280 so
After 280 seconds they toll together. Every 4.6 minutes toll together
13 times they toll together in one hour.
- 12 years agoHelpfull: Yes(0) No(12)
- 102
find the LCM of 3,5,7,8,10 and divide it by 24*60*60 - 12 years agoHelpfull: Yes(0) No(5)
- LCM of 3,5,7,8,10 = 840 secs = 14 mins
After every 14 mins, the bells will toll together.
At begining of the hour, they toll together.
so the bells will toll together 1+4= 5 times in 1 hour. - 2 years agoHelpfull: Yes(0) No(0)
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