The sides of a right-angled triangle have lengths, which are integers in arithmetic progression.There exists such a triangle with smallest side having length of
A) 2000 units B)2001 units C)2002 units D)2003 units E)1999 units

• (3,4,5) form a pythagorean triplet...so smallest side must be multiple of 3...its (B) 2001
• 12 years agoHelpfull: Yes(4) No(0)
• sol:B =2001
  
  SIDES ARE IN AP=> a-d,a,a+d
  a+d is hypotenuse (longest side)
  in RIGHT ANGLED TRIANGLE:
  (a+d)^2=a^2+(a-d)^2
  solving this, a=4d=>a-d=3d
  "a-d" is smallest side and clearly divisible by 3(a-d)=3*d
  2001 IS SMALLEST POSSIBLE SIDE
• 12 years agoHelpfull: Yes(2) No(0)
• the answer is 2001.since the sides are in AP so with the given terms a,a+d,a-d apply pythagoras th. and in the end the result has to be a multiple of three and here only one term follows the above condition...
• 12 years agoHelpfull: Yes(0) No(0)