A sum was put at SI at certain rate for 2 years Had it been put at 3 higher rate

let P be the sum.and X be the interest rate.
(2*(X+3)*P/100) - (2*X*P/100)=300
THEREFORE 6P/100=300
P=RS 5000
12 years agoHelpfull: Yes(11) No(0)

3%=300 for 2 yrs
3%=150 for 1 yr
1%=50
therefore 100% = 5000
so, SUM = Rs 5000
12 years agoHelpfull: Yes(3) No(2)
1st case: si=p*2*r/100
2nd case: si+300=p*2(r+3)/100
on equating 2pr/100=2pr/100+6p/100-300
6p=30000
p=5000
12 years agoHelpfull: Yes(3) No(1)
p=x
t=2
r=3
s.i = 300
p= s.i*100/ t*r

p = 300*100/2*3
= 5000
12 years agoHelpfull: Yes(1) No(0)
we know interest rate is p*t*r/100
given t=2 then si=p*2*r/100
and 300 more the rate 3% high i.e,
si+300=p*2*(3=r)/100
equating both
6p=30000
p=5000
12 years agoHelpfull: Yes(1) No(0)
3% m0re=300rs.
=>100%=10000
so,sum=Rs.10,000
12 years agoHelpfull: Yes(0) No(4)
one interest 3=>2 years=6%=300(6*50=300)
sum= 100%=5000(100*50)
12 years agoHelpfull: Yes(0) No(0)
sum=more money *100/more rate*tme
sum=300*100/3*2
sum=30000/6
sum=5000
9 years agoHelpfull: Yes(0) No(0)
p*(R+3)*2/100=p*R*2/100+300
6p=30000
p=5000
sum is 5000
7 years agoHelpfull: Yes(0) No(0)

A sum was put at SI at certain rate for 2 years.Had it been put at 3% higher rate, it would have fetched Rs.300 more.Find the Sum