A person expends the money as much as double plus Rs one, what he had expended on earlier day, After six days his total expenses was found to be Rs 120.With what amount had he started his expenses on day one ?

• Rs.1 he spent on day 1.
  
  1st day he spent = 1
  2nd day he spent = 3
  3rd day he spent = 7
  4th day he spent = 15
  5th day he spent = 31
  6th day he spent = 63
  
  After six days, he spent = 1+3+7+15+31+63 = 120
• 12 years agoHelpfull: Yes(2) No(1)
• with 1 Rs he started his expenses on day one.
  let us take his day one expenditure is x.
  then first day expenditure is x+1
  second day 2(x+1)+1=2x+3
  third day 2(2x+3)+1=4x+7
  like that we have 8x+15,16x+31,32x+63 for forth fifth and sixth day
  then
  (x+1)+(2x+3)+(4x+7)+(8x+15)+(16x+31)+(32x+63)=120
  by soving this we get x=0
  so first day expenditure is x+1=0+1=1.I think this is the longest method..
  can anyone tell me the simple procedure
• 12 years agoHelpfull: Yes(2) No(0)