The length of a rope, to which a cow is tied, is increased from 19m to 30m. How much additional ground will it be able to graze? Assume that the cow is able to move on all sides with equal ease.
a. 1696 sq m
b. 1694 sq m
c. 1594 sq m
d. 1756 sq m

• ANS IS : 1694
  AREA OF CIRCLE IS = PI*R^2
  GRAZING AREA IS=19M
  =22/17*19^2
  WHEN IT IS INCREASED LENGTH IS =22/17*30^2
  THEREFORE ADDITIONAL GROUND WILL IT BE ABLE TO GRAZE=22/7(30^2-19^2)
  =22/7*((30^2-19^2))
  =1694
• 9 years agoHelpfull: Yes(16) No(0)
• SIMPLE CHECK
  30-19=11
  1696/11 LEAVING REMAINDER
  1694/11=154 WITH NO REMAINDER
  SO ANS IS 1694 SQ M
• 9 years agoHelpfull: Yes(5) No(0)
• 
  1694
  As area of circle is pi*r2
  So 3.14* 19sqr =1133.54
  3.14*30sqr= 2862
  2862-1133= 1694
• 9 years agoHelpfull: Yes(2) No(0)
• b. pi(30^2-19^2)
  3.14*539=1692.46
• 9 years agoHelpfull: Yes(0) No(0)