3 milkmen A B C rented a pasture A grazed his 45 cows for 12 days B grazed his 36

A=45*12=540
B=36*15=540 ( condition already given his rent was 540)
c=60*10=600
total rent=540+540+600=1680
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d.1680
45*12*x=540
x=1
36*15=540
60*10=600
540+540+600=1680
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A B C
cows- 45 36 60
days- 12 15 10
rent- - 540 -
Rs540 for 15 days
? for 1 day
540/15=Rs.36
Therefore, Rs.36 per 1 day for 36 cows
i.e, Rs.1 for 1 cow per 1 day
so, A rent Rs.540 (45*12)
B rent Rs.540
C rent Rs.600 (60*10)
540+540+600=1680
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Ans is 1680
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(45*12)+(36*15)+(60*10)=1680
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540:540:600=9:9:10
(9+9+10)*60=1680
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Ans is :1680
A=45*12=540
B=36*15=540
C=60*10=600
540:540:600=9:9:10
9 PART IS EQUAL TO RS 540=
1 PART IS=540/9=RS 60
SO TOTAL RENT IS=(9+9+10)*60=28*60=1680
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3 milkmen A, B, C rented a pasture. A grazed his 45 cows for 12 days, B grazed his 36 cows for 15 days and 60 cows for 10 days. If B’s share of rent was Rs 540, what is the total rent?
a. Rs. 1000
b. Rs. 1320
c. Rs. 1540
d. Rs. 1680