the letters in the word ROADIE are permuted in all possible ways and arranged in alphabetical order. find the word in 44 rank.

• A[DEIOR] =5!=120 NOT POSSIBLE
  AD[EIOR] = 4! = 24
  AE[DIOR] = 4! = 24
  AED[1OR] = 3! = 6+24=30
  AEI[DOR] =3! = 6+30 =36
  AEO[DIR] = 3! = 36+6 =42
  NOW 43RD LETTER WOULD BE AERDIO
  AND HENCE 44TH IS AERDOI
  
• 10 years agoHelpfull: Yes(40) No(7)
• A D - - - - =4!=24
  A E D - - -= 3!=6
  A E I - - -=3!=6
  A E O - - - =3!=6
  A E R D I O=1
  A E R D O I=1
  
  so 44th no is AERDOI
• 10 years agoHelpfull: Yes(6) No(0)
• KARTHIKEYANK can u please tell me more clearly..how did u take 6+24, 6+30, 36+6 and why Ist one is not possible
• 10 years agoHelpfull: Yes(2) No(0)
• AD----=4!=24
  ADE___=3!=6
  ADI___=3!=6
  ADO___=3!=6
  ADOEIR=1
  ADOIER=1
  24+6+6+6+1+1=44=ADOEIR
• 10 years agoHelpfull: Yes(2) No(3)
• can any one explain me that why we r taking AE[DIOR]
• 10 years agoHelpfull: Yes(0) No(1)
• becoz it is the alphabetical order
• 10 years agoHelpfull: Yes(0) No(0)
• please explain clear
• 10 years agoHelpfull: Yes(0) No(0)