Elitmus
Exam
Numerical Ability
Data Sufficiency
If m and n are two positive integers, then what is the value of mn?
(1)7m + 5n= 29
(2) m + n= 5
Read Solution (Total 34)
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- its not elitmus level que..
- 11 years agoHelpfull: Yes(70) No(9)
- it can be solved using 1 statement alone....and thats d reason it's a elit ques becoz most of us will solve it using both equation and choose the wrong ans
- 10 years agoHelpfull: Yes(21) No(10)
- its a tricky question....most of the student will say both the statements are required to answer the question....
but in this particular question option1 is sufficient to ans the question....
because 7m+5n=29 this is satisfied only possibilties value of m=2 and n=3 and no more ans is possible in hit n trial also it has a unique solution
but in the second statement we can determine the value of m and n in different ways....saucha as 1+5
2+4,3+3,4+2
if the same situation arises in the first equation then we should combine the two equation....
but here only 1st statemen is sufficient should be the ans.... - 9 years agoHelpfull: Yes(13) No(1)
- mn=6
7m +5n = 29
2m +5(m+n)=29
from second equation putting the value of m+n =5
2m=4 and m=2 hence by second equation again n=3 so mn=6 - 12 years agoHelpfull: Yes(11) No(10)
- 7m + 5n = 29
m + n = 5(multiply both sides by 7)
subtract equation second from first,we get
7m + 5n =29
7m + 7n = 35
n = 3
substitute value of n in any equation.
m = 2
mn = 6.
- 12 years agoHelpfull: Yes(9) No(6)
- both the equations are needed .....it cant solve alone with any equation..
- 10 years agoHelpfull: Yes(7) No(10)
- m=2
n=3
mn=6 - 11 years agoHelpfull: Yes(6) No(1)
- Ans - only 1st is sufficient.
from eq 1, m = 7 , n= -4 but in question given that m & n are +ve
again check that if the value of m, n exceed from 3 than we cant be get 29
so check for 0, 1, 2, 3 by suing both stmnts we can find m=2,n=3 but as ist is data sufficiency 1st stmnt is sufficient - 9 years agoHelpfull: Yes(6) No(0)
- 7m+5n=29
7m+7n=35 (Multiplying with 7 )
n=3 - 12 years agoHelpfull: Yes(3) No(4)
- Even its not for any Aptitude test..
- 11 years agoHelpfull: Yes(2) No(3)
- Ans - only 1st is sufficient.
from eq 1, m = 7 , n= -4 but in question given that m & n are +ve
again check that if the value of m, n exceed from 3 than we cant be get 29, so check for ( 0, 1, 2, 3) & got (m,n)=(2,3) satisfy. - 10 years agoHelpfull: Yes(2) No(1)
- We need both statement to answer this question. Because we cannot rely on hit n trial method if 29 is greater then 100. So,
7m + 5n = 29..... (i)
m + n = 5.... (ii)
by taking m = 5-n from (ii) put in eq. (i)
then
7 (5-n) + 5n = 29
35 - 7n + 5n =29
6 = 2n
n = 3 put this value in eq. (ii)
so m = 5-3
m = 2.
So both statement required. - 10 years agoHelpfull: Yes(2) No(5)
- he..he...hehhhe...funny question
- 11 years agoHelpfull: Yes(1) No(3)
- It can be answered using either options by hit and trial method.
- 10 years agoHelpfull: Yes(1) No(3)
- ans=6
7m+5n=29
-
5m+5n=25
2m=4
m=2
n=3
- 9 years agoHelpfull: Yes(1) No(0)
- we don't have to assume anything in data sufficieny . if we can find the solution through option itself then its valid
- 9 years agoHelpfull: Yes(1) No(0)
- m=2
n=3
mn=6 - 9 years agoHelpfull: Yes(1) No(0)
- mn=6
by solving two equations (1) & (2) - 10 years agoHelpfull: Yes(0) No(0)
- 6
2+3=5
m=2 n=3
mn=6
- 10 years agoHelpfull: Yes(0) No(1)
- both are required combine to give solution
- 10 years agoHelpfull: Yes(0) No(1)
- both are required combine to give solution
- 10 years agoHelpfull: Yes(0) No(1)
- 2+3=5
m=2 n=3
mn=6 - 10 years agoHelpfull: Yes(0) No(0)
- m=2 n=3 mn=6
stament 1 alone sufficient 2 alone sufficient both also......which one we have to select? - 10 years agoHelpfull: Yes(0) No(0)
- First of all, I think you should type the given equation as
33 w + 32 x + 3y + z= 34,
Since w & x are non-negative integers,
both w and x cannot be greater than 0.
In other words, one of w and x must be 0.
When w =0, we have 32 x + 3 y + z = 34.
If x = 0,then 3y+z = 34.
But both y & z are less than 3, so 3y + z - 10 years agoHelpfull: Yes(0) No(0)
- it can be solved using 7m+5n=29
logically value of m can not more then 3
put m=1
5n=22 it can not be satisfied
put m=2 5n=15 then we got n=3
problem solved using statement 1 only - 9 years agoHelpfull: Yes(0) No(0)
- m=2 and n=3 is the only condition which satisfy both statements
- 9 years agoHelpfull: Yes(0) No(1)
- Actually it might have been data sufficiency question and so maybe here it seems simple to solve but in that case it will be a little tricky as only 1st option is sufficient enough to solve it.
- 9 years agoHelpfull: Yes(0) No(0)
- 7m+5n
=7*2 + 5*3
=14 + 15
=29
.'.7m + 5n = 29 &, m + n = 5.
m + n= 5
=2+3
=5
m=2 & n=3,
the value of mn= (2*3)= 6. - 9 years agoHelpfull: Yes(0) No(0)
- 7m+5(5-m)=29
7m+25-5m=29
m=2;
n=3;
m*n=6; - 9 years agoHelpfull: Yes(0) No(0)
- 7m+5n=29
m+n=5
multiply by 5 in 2nd equation and sub from equation 2
7m+5n=29
5*(m+n=5)
7m+5n=29
-5m-5n=-25
2m=4
m=2
put the value of m in any equation
2+n=5
n=3
m=2
n=3 - 9 years agoHelpfull: Yes(0) No(0)
- multiply second equation with 5
and cancel 5n
then 2m=4
so m=2 - 9 years agoHelpfull: Yes(0) No(0)
- simple equation solving problem from 2)n=5-m and substitute n value in first equation and get m=2 and put that m value in 2 then n=3
So ans m=2,n=3 - 9 years agoHelpfull: Yes(0) No(0)
- only statment two is correct to give the answer
- 8 years agoHelpfull: Yes(0) No(3)
- it can be solved by 1st eqn only bcoz the unique sol of 1st eqn is where m=2 n=3 .
- 6 years agoHelpfull: Yes(0) No(0)
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