If m and n are two positive integers, then what is the value of mn?

(1)7m + 5n= 29
(2) m + n= 5

• its not elitmus level que..
• 11 years agoHelpfull: Yes(70) No(9)
• it can be solved using 1 statement alone....and thats d reason it's a elit ques becoz most of us will solve it using both equation and choose the wrong ans
  
• 10 years agoHelpfull: Yes(21) No(10)
• its a tricky question....most of the student will say both the statements are required to answer the question....
  but in this particular question option1 is sufficient to ans the question....
  because 7m+5n=29 this is satisfied only possibilties value of m=2 and n=3 and no more ans is possible in hit n trial also it has a unique solution
  but in the second statement we can determine the value of m and n in different ways....saucha as 1+5
  2+4,3+3,4+2
  if the same situation arises in the first equation then we should combine the two equation....
  but here only 1st statemen is sufficient should be the ans....
• 9 years agoHelpfull: Yes(13) No(1)
• mn=6
  
  7m +5n = 29
  2m +5(m+n)=29
  from second equation putting the value of m+n =5
  2m=4 and m=2 hence by second equation again n=3 so mn=6
• 12 years agoHelpfull: Yes(11) No(10)
• 7m + 5n = 29
  m + n = 5(multiply both sides by 7)
  subtract equation second from first,we get
  7m + 5n =29
  7m + 7n = 35
  n = 3
  substitute value of n in any equation.
  m = 2
  mn = 6.
  
  
• 12 years agoHelpfull: Yes(9) No(6)
• both the equations are needed .....it cant solve alone with any equation..
• 10 years agoHelpfull: Yes(7) No(10)
• m=2
  n=3
  mn=6
• 11 years agoHelpfull: Yes(6) No(1)
• Ans - only 1st is sufficient.
  from eq 1, m = 7 , n= -4 but in question given that m & n are +ve
  again check that if the value of m, n exceed from 3 than we cant be get 29
  so check for 0, 1, 2, 3 by suing both stmnts we can find m=2,n=3 but as ist is data sufficiency 1st stmnt is sufficient
• 9 years agoHelpfull: Yes(6) No(0)
• 7m+5n=29
  7m+7n=35 (Multiplying with 7 )
  
  n=3
• 12 years agoHelpfull: Yes(3) No(4)
• Even its not for any Aptitude test..
• 11 years agoHelpfull: Yes(2) No(3)
• Ans - only 1st is sufficient.
  from eq 1, m = 7 , n= -4 but in question given that m & n are +ve
  
  again check that if the value of m, n exceed from 3 than we cant be get 29, so check for ( 0, 1, 2, 3) & got (m,n)=(2,3) satisfy.
• 10 years agoHelpfull: Yes(2) No(1)
• We need both statement to answer this question. Because we cannot rely on hit n trial method if 29 is greater then 100. So,
  7m + 5n = 29..... (i)
  m + n = 5.... (ii)
  
  by taking m = 5-n from (ii) put in eq. (i)
  then
  7 (5-n) + 5n = 29
  35 - 7n + 5n =29
  6 = 2n
  n = 3 put this value in eq. (ii)
  so m = 5-3
  m = 2.
  So both statement required.
• 10 years agoHelpfull: Yes(2) No(5)
• he..he...hehhhe...funny question
  
• 11 years agoHelpfull: Yes(1) No(3)
• It can be answered using either options by hit and trial method.
• 10 years agoHelpfull: Yes(1) No(3)
• ans=6
  7m+5n=29
  -
  5m+5n=25
  2m=4
  m=2
  n=3
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• we don't have to assume anything in data sufficieny . if we can find the solution through option itself then its valid
• 9 years agoHelpfull: Yes(1) No(0)
• m=2
  n=3
  mn=6
• 9 years agoHelpfull: Yes(1) No(0)
• mn=6
  by solving two equations (1) & (2)
• 10 years agoHelpfull: Yes(0) No(0)
• 6
  2+3=5
  m=2 n=3
  mn=6
  
• 10 years agoHelpfull: Yes(0) No(1)
• both are required combine to give solution
• 10 years agoHelpfull: Yes(0) No(1)
• both are required combine to give solution
• 10 years agoHelpfull: Yes(0) No(1)
• 2+3=5
  m=2 n=3
  mn=6
• 10 years agoHelpfull: Yes(0) No(0)
• m=2 n=3 mn=6
  stament 1 alone sufficient 2 alone sufficient both also......which one we have to select?
• 10 years agoHelpfull: Yes(0) No(0)
• First of all, I think you should type the given equation as
  33 w + 32 x + 3y + z= 34,
  Since w & x are non-negative integers,
  both w and x cannot be greater than 0.
  In other words, one of w and x must be 0.
  When w =0, we have 32 x + 3 y + z = 34.
  If x = 0,then 3y+z = 34.
  But both y & z are less than 3, so 3y + z
• 10 years agoHelpfull: Yes(0) No(0)
• it can be solved using 7m+5n=29
  logically value of m can not more then 3
  put m=1
  5n=22 it can not be satisfied
  put m=2 5n=15 then we got n=3
  problem solved using statement 1 only
• 9 years agoHelpfull: Yes(0) No(0)
• m=2 and n=3 is the only condition which satisfy both statements
• 9 years agoHelpfull: Yes(0) No(1)
• Actually it might have been data sufficiency question and so maybe here it seems simple to solve but in that case it will be a little tricky as only 1st option is sufficient enough to solve it.
• 9 years agoHelpfull: Yes(0) No(0)
• 7m+5n
  =7*2 + 5*3
  =14 + 15
  =29
  
  .'.7m + 5n = 29 &, m + n = 5.
  
  m + n= 5
  =2+3
  =5
  
  m=2 & n=3,
  the value of mn= (2*3)= 6.
• 9 years agoHelpfull: Yes(0) No(0)
• 7m+5(5-m)=29
  7m+25-5m=29
  m=2;
  n=3;
  m*n=6;
• 9 years agoHelpfull: Yes(0) No(0)
• 7m+5n=29
  m+n=5
  multiply by 5 in 2nd equation and sub from equation 2
  7m+5n=29
  5*(m+n=5)
  7m+5n=29
  -5m-5n=-25
  2m=4
  m=2
  put the value of m in any equation
  2+n=5
  n=3
  m=2
  n=3
• 9 years agoHelpfull: Yes(0) No(0)
• multiply second equation with 5
  and cancel 5n
  then 2m=4
  so m=2
• 9 years agoHelpfull: Yes(0) No(0)
• simple equation solving problem from 2)n=5-m and substitute n value in first equation and get m=2 and put that m value in 2 then n=3
  
  So ans m=2,n=3
• 9 years agoHelpfull: Yes(0) No(0)
• only statment two is correct to give the answer
  
• 8 years agoHelpfull: Yes(0) No(3)
• it can be solved by 1st eqn only bcoz the unique sol of 1st eqn is where m=2 n=3 .
• 6 years agoHelpfull: Yes(0) No(0)