One tap can fill a water tank four times as fast as another tap. If together the two taps can fill the water tank in 30 minutes then the slower tap alone will be able to fill the water tank in _______ .

• Let the slower pipe alone fill the water tank in t minutes.
  
  Then, faster pipe will fill it in t/4 minutes.
  
  Therefore, 1/t + 4/t = 1/30
  
  =>5/t = 1/30
  
  Now solve for t.
  
  => t=150 min
• 11 years agoHelpfull: Yes(22) No(2)
• Faster pipe takes time T1
  Slower pipe takes time T2
  We know T1 = 4T2
  
  part filled in 1 min
  1/T1 + 1/T2 = 1/30
  
  1/4T2 + 1/T2 =1/30
  solve for T2, u get T2= 75/2 = 37.5
  i.e slower tap alone takes 37min 30sec to fill the tank
  
• 11 years agoHelpfull: Yes(5) No(13)
• Let faster tap fills the tank in x minutes then slower tap will fill that tank in 4x minutes
  let the volume of tank is V
  then rate of fast tap is (s1) = V/x
  and rate of slower tap is (s2)= V/4x
  and according to question
  s1+s2= V/30
  in this equation if we put the value of s1 and s2 it will give
  V/x + V/4x =V/30
  5/4x=1/30
  4x=150 minutes it means
  slower tap alone will fill the tank in 150 minutes :)
  
• 11 years agoHelpfull: Yes(3) No(0)
• ratio of speed of two tanks=1:4
  so part of water filled in constant time will also be 1:4
  means in 30 mins ta[1] filled 1/5 part n tap [2] filled 4/5 part..
  so by unitary method...
  ta[1] filled 1/5 part in 30 mins.
  so to fill whole tank it el take 30*5=150 mins
  
• 10 years agoHelpfull: Yes(3) No(0)
• let time taken by slower tap = t
  then,time taken by faster tap = t/4
  total time taken is given by 30 minutes.
  1/t + 4/t = 1/30
  5/t = 1/30
  => t = 150seconds
• 11 years agoHelpfull: Yes(2) No(3)
• let faster tap can fill water tank in x min.
  Then slower will fill in 4x min
  now, a/c to ques,
  both can fill in 30 min, 1 tank full
  so, in 1 min they can fill 1/30 of the tank
  again,
  in x min faster can fill the tank full
  so,in 1min it can fill 1/x of the tank
  similarly, in 1 min slower can fill 1/4x of the tank
  now,
  1/x + 1/4x = 1/30
  by solving,
  x=6
  hence slower can fill tank in 6*4=24 min
• 11 years agoHelpfull: Yes(0) No(12)
• ans) 150mins
  soln)-
  let the faster tap fill the tank in x mins
  so slower tap will fill in 4x mins
  both togrther can fill in 30mins =(x*4x)/(x+4x)
  =(4x^2)/5x
  therefore,by calculating above eqn
  4x=150mins
  hence slower pipe takes 150mins to fill the tank alone.
• 11 years agoHelpfull: Yes(0) No(1)
• (1/x)+(4/x)=1/30
  5/x=1/30
  x=150
• 4 years agoHelpfull: Yes(0) No(0)