Others Maths Puzzle

there are ten children (aged 1 to 10 years)who have equal amounts of money. in the first transaction the eldest child gives one rupee to every child younger to him. in the second transaction , the second eldest child gives one rupee to every child younger to him.this type of distribution continues for the next two transactions. in the end the total sum with the children who have given money to other children is half the sum of money with children who did not give any money. what was the original amount with each child?
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The answer is: each child had originally Rs.42 each
Let each child had originally Rs.x
The eldest child parted Rs.9, so he has now x-9
Similarly, the next eldest has now x-8
the next two eldest has now x-7 and x-6 only
THE TOTAL SUM OF MONEY WITH THEM=4X-30
Similarly, those who have not distributed the money
They have 6x+24
Now the equation is 4x-30=1/2(6x+24)
Solving, we get x=Rs.42
12 years agoHelpfull: Yes(1) No(2)

The answer is : Rs.36
Let each child had originally Rs.x
as four eldest child distributed, after distribution they have now
6x-24(x-9+x-7+x-5+x-3)
The money with the remaining children would be 6x+24
Now the equation is:
4x-24=1/2(6x+24)
Now. solving x=Rs.36
12 years agoHelpfull: Yes(1) No(1)

Others Other Question

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