A square is drawn inside a right angled triangled with the two perpendicular sides as 12cm and 8cm.what is the side of the largest possible square that can be drawn?
(A)4cm (B)4.8cm (C)4.5cm (D)4.4cm (E)5cm

• 
  Consider the origin as the point of right angle
  So, (8,0)and (0,12) are the 2 vertices.
  Equation of hypotenuse : 8y+12x=96
  Now solve this with y=x(the diagonal of the largest square)
  x=4.8, y=4.8
• 14 years agoHelpfull: Yes(10) No(0)
• area of triangle=.5*8*12= 48
  let the side of square is= x
  so, x^2 + 0.5*x(8-x) + 0.5*x(12-x)=48
  so, 4x-0.5x^2+x^2+6x-0.5x^2=48
  10x=48
  x=4.8
  ans=option(B)
  
• 14 years agoHelpfull: Yes(6) No(0)
• let x is the size of square then
  tan
• 14 years agoHelpfull: Yes(1) No(2)