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Numerical Ability
Ratio and Proportion
Five kids were sharing out a box of candies. Amar took one-third, Babu took one-quarter,Chetan took one-fifth, and Dinakar took one-sixth. That left six candies as Shiva's share. Howmany candies were altogether?
Read Solution (Total 4)
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- let the total no of candies in a box= x
then aman took=x/3
babu took=x/4 and chetan took = x/5 and the remaining should be shiva's share
then
x-(x/3+x/4+x/5+x/6) =6 i.e 3x/60=6
therefore x=120
- 12 years agoHelpfull: Yes(16) No(1)
- let the total number of candies be x,
Amar share = x/3,
babu share = x/4,
chetan share = x/5,
dinakar share = x/6,
shiva's share = 6,
x = x/3 + x/4 + x/5 + x/6 + 6
x = 120 - 12 years agoHelpfull: Yes(8) No(1)
- x/3+x/4+x/5+x/6+6=x
.05x=6
x=120.so 120 candies were there alltogether. - 12 years agoHelpfull: Yes(0) No(0)
- 1/3x+1/4x+1/5x+1/6x 100
- 12 years agoHelpfull: Yes(0) No(2)
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