general Maths Puzzle

If 3 numbers of three faced dice with numbers 2,5 and 8 on its faces are to be thrown. What is the minimum number of tries required to get the sum, which is exact multiple of 9 ?

Read Solution (Total 2)

Minimum 3 tries required.

Possibility 1 : 2,2,5 -->
1st try: 2, 2nd try: 2, 3rd try: 5
(2+2+5 = 9) (i.e, 9 is divisible by 9)

Possibility 2 : 2,8,8 --> (
1st try:2, 2nd try:8 , 3rd try: 8
(2+8+8= 18) (i.e, 18 is divisible by 9)
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Minimum 3 tries required
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