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Variable R and S are related by the equation R=1/S2(1 by S square).now,if S is increased by 10%,what will happen to R?
(A)R decreased by 19% (B)R decreased by 10% (C)R decreased by 17% (D)R decreased by 21% (E)R increased by 21%
Read Solution (Total 3)
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- r=1/s^2
r'=1/(s+.10s)^2
r-r'=.1735/s^2
% decrease=r-r'/r*100=17 ans - 14 years agoHelpfull: Yes(10) No(1)
- Ans is C
- 14 years agoHelpfull: Yes(1) No(1)
- R=1/S^2
R1=1/S1^2
S1=11/10S
R1=1/(11/10S)^2 OR R1=100/121S^2 OR R1= R *(100/121 )
R-R1= R(1- 100/121) OR R-R1=R*(21/100)
DECREASING PERCENTAGE IS =100*21/121
=17.355 - 14 years agoHelpfull: Yes(1) No(3)
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