Find solutions of
A^2 = B^3 − 432.GIVEN THAT A and B are integers.

• SORRY , SOME TYPING ERROR!!!
  − MEANS -
• 12 years agoHelpfull: Yes(1) No(2)
• A = 36 ; B = 12
  
  A^2 = B^3 - 432
  36^2 = 12^3 - 432
  1296 = 1728 - 432
  1296 = 1296
  Proved.
• 12 years agoHelpfull: Yes(1) No(1)
• A = 36
  
  B = 12
  
  A^2 = B^3 - 432
• 12 years agoHelpfull: Yes(1) No(1)
• a=3 and
  b=4
• 12 years agoHelpfull: Yes(0) No(2)
• question has typo errors. Hence it is closed
• 12 years agoHelpfull: Yes(0) No(1)
• A=+36 OR -36
  B=12
  B^3 = A^2 + 432 is a perfect cube IMPLIES THAT 6^3(A^2 + 432) = 216(A^2 + 432) is a perfect cube.
  But 216(A^2 + 432) = (A + 36)^3 − (A − 36)^3.
  
  
  Hence (6B)^3 + (A− 36)^3 = (A + 36)^3.
  
  a^n + b^n = c^n has no non-zero integer solutions for a, b and c, when n > 2
  So here solution exists when A=+36 OR -36
  In this case 6B=72
  B=12
• 12 years agoHelpfull: Yes(0) No(0)