A sum 's' is divided into 4 parts. second person gets Rs 10
more than first.3rd person is Rs 10 more than second,4th is 10 more than 3rd.how much amount do 1st person get.?

• let x be amount getting by first person,
  second person gets x +10,third person gets x + 20,fourth person gets x + 30,
  now s = (x)+(x+10)+(x+20)+(x+30)
  s = 4x + 60
  s - 60 = 4x
  or x = (s-60)/4
• 11 years agoHelpfull: Yes(32) No(1)
• 1st person gets Rs.(s-60)/4
  
  Let us assume that 1st person gets Rs.x
  then 2nd will get Rs.x+10
  3rd will get Rs.x+20
  4th will get Rs.x+30
  
  then the sum s=x+(x+10)+(x+20)+(x+30)
  => s=4x+60
  => 4x=s-60
  => x=(s-60)/4
  Therefore 1st pesron will get Rs.(s-60)/4
• 11 years agoHelpfull: Yes(11) No(1)
• a,b,c,d are the four persons...
  
  b=10+a;
  c=10+b;
  d=10+c;
  
  a+b+c+d is the total amount 'S'
  
  then substituing the values in terms of A :
  a+10+a+20+a+30+a+40+a
  5a will be 100 , so a=20.....
  
  which is a=(s-60)/4 as mentioned above........
  
• 11 years agoHelpfull: Yes(8) No(1)
• Let us assume that 1st person gets Rs.x
  then 2nd will get Rs.x+10
  3rd will get Rs.x+20
  4th will get Rs.x+30
  
  then the sum s=x+(x+10)+(x+20)+(x+30)
  s= 4x+60/4
• 11 years agoHelpfull: Yes(1) No(4)
• Let assume 1 get x amount, so 2 gets 10+x, 3 gets 10+10+x
  and 4 gets 10+10+10+x
  so,
  S=x+10+x+10+10+x+10+10+10+x
  S=4x+60
  S-60=4x
  S/4-60/4=x
  S/4-15=x
  Let we Assume S=100
  100/4-15=x
  25-15=x
  So, x=10
  So, 1 gets 10,2 gets(10+x)=20,3 gets 30,4 gets 40
  So, S=10+20+30+40
  S=100
  
• 11 years agoHelpfull: Yes(1) No(8)