The age of father is twice that of the elder son, Ten years hence the age of father will be three times that of the younger son. If the difference of ages of the two sons is 15 years, then what is the of father?

• Let age of elder son = x
  And age of father = 2x
  Age of younger son, Y = (x-15)
  After 10 years
  2x+10=3(x-15+10)
  2x+10=3(x-5)
  3x-2x=25
  x=25;Y=10;2x = 50
  Father's age = 50
• 11 years agoHelpfull: Yes(5) No(1)
• Father's age = 50
  
  Let age of elder son = x
  And age of father = 2x
  Age of younger son, Y = (x-15)
  After 10 years
  2x+10=3(x-15+10)
  2x+10=3(x-5)
  3x-2x=25
  x=25;Y=10;2x = 50
  Father's age = 50
• 11 years agoHelpfull: Yes(3) No(3)
• Let the age of the elder son is x
  then, father's age would be 2x
  Ten years hence, the father's age shall be 2x+10
  and the age of the elder son would be x+10
  and the age of the younger son be (2x+10)/3
  Now the equation is :( difference between the ages of sons)
  (x+10)-(2x+10)/3=15
  solving, we get x=25
  and the father's age would be 25*2=50years
• 11 years agoHelpfull: Yes(3) No(1)
• Father's age is 50 yrs.
  Age of elder son = 25 yrs
  age of younger son = 10 yrs
• 11 years agoHelpfull: Yes(1) No(0)