A cylindrical container of radius 6 cm and height 15 cm is filled with ice-cream. The whole icecream has to be distributed to 10 children in equal cones with hemispherical tops. If the height of the conical portion is four times the radius of its base, find the radius of the ice-cream cone.

• radius =3cm
  
  volume of given ice cream =(pie)*6²*15=540(pie)
  
  dividing to 10 children volume given to a child =54(pie)
  
  let r be radius and h be the height of the cone,then
  
  (pie)r²h/3 + 2(pie)r³/3=54(pie)
  
  also given h=4r
  
  4r³/3 +2r³/3=54
  
  2r³=54
  
  r³=27
  
  r=3
• 12 years agoHelpfull: Yes(8) No(0)
• the formula for volume of sphere is (4/3)pi*r^3.
  thus volume of hemispherical top is given by (2/3)pi*r^3.
  so total volume of ice_cream is ((pi/3)*r^2*h)+(2/3)pi*r^3=pi*r^2((h/3)+(2r/3)).
  volume of cylinder ll be 540pi.
  volume of cone is 540pi/10=54pi.
  on substitution v get the answer.
  
• 12 years agoHelpfull: Yes(1) No(1)