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Pargat Pal Singh 6 Days ago

Dear Admin,
Is there any chance of fair evaluation of scores or results are pre-decided to give prizes to a few privileged members ?

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Karan 5 Days ago

No chance. I think Admin team is working from home. :)

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Ishfaq Ahmad to Devendra Marghade 29 Days ago

A train passes a standing man 11.3 seconds and passes a bridge of length 396m in 18 seconds .the speed of the train is

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Devendra Marghade 26 Days ago

Let the speed of the train be x m/sec and length of the train be y m, then y/x=11.3 or y - 11.3x = 0 --(i)
Also, (y + Length of platform)/x=18
(y+396)/x=18 => 18x-y=396 ---(ii)
Solving (i) & (ii), we get, x=59.10 and y=667.88
Hence speed of the train is 59.10 m/s

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Ishfaq Ahmad 29 Days ago

When you keep believing, keep trying and keep doing... Someday, you will succeed.

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Shubhashish Sinha 1 Month ago

Find the elements in the relation "have the same remainder when divided by 8" if the
relation is defined on {1, 2, 3 .... 24, 25}. Also, find the distinct equivalence classes
of this equivalence relation.

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Sai laxmi Nomula 1 Month ago

the average number of people visitedredfort on every day is 2240.but 2200 on every saturday, 3000 on sunday and on wednesday it is 1500people visited . what is the average number of people visited on remaining days in the ,month of december when there are 4 thursdays abd 4 mondays in the month?

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G.S.Kantharao 1 Month ago

Average Visited in December = 2240
Then total visitors = 2240*31 = 69440
As there are 4 Thursdays and 4 Mondays the other 3 are Sunday,Friday and Saturday. It means 5 Sundays 5 Fridays and 5 Saturdays
It means 5*2240+5*2200+5*3000=11200+11000+15000=37200
Remaining=69440-37200=32240
Average of remaining=32240/16=2015
So Average =2015

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allam vishwaja 1 Month ago

help me for placements

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rohit ranjan 1 Month ago

please give more details ?

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karthik 1 Month ago

Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?

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naveen 2 Months ago

Long ago a princess wanted

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nandy ram 3 Months ago

during a period of decline in a stock market prices a stock sold at ₹50/share on the first day,₹40/share on the second day and ₹25 on the third day.If a invester bought 100,120&180 shares on the respective 3 days the average price paid per share will be?.

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Devendra Marghade 2 Months ago

Avg. Price = (100*50 + 120*40 + 180*25) / (100+120+180) = 35.75

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Karakavalasa sai manohar 3 Months ago

Help me to get score in tcs nqt 2021

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TAVVA PAVAN KUMAR 3 Months ago

On Feb 18 I have TCS NQT can some one help me friends

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Meghavath Madhu Naik 3 Months ago

A man sets out by cycle from Delhi to Rohtak, and at the same time another man starts from Rohtak by cycle to Delhi. After passing each other they complete their journeys in 3 1/3and 4 4/5 hours respectively. At what rates does the second
man cycle if the first cycles at 8 km per hour?

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G.S.Kantharao 3 Months ago

Let A and B are the persons.
A travelled x km,B travelled y km before they meet.
Time taken for A and B to reach their destinations are 10/3h,24/5h
Speeds are y/(10/3),x/(24/5)
At the time they meet they travelled same time => x/(3y/10)=y/5x/24)
10x/3y = 24y/5x=>50x^2=72y^2
=>x^2/y^2=72/50
x/y=√(1.44)=1.2
=>x=1.2y
Total distance =(x+y)=(x+x/1.2)=2.2x/1.2=11x/6
Now time taken for B=(11x/6)/(5x/24)
=11*24/6*5=44/5=8h 48m

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JACK KISSER 3 Months ago

ORDER RESEARCH CHEMICALS FROM https://www.highgradeschemicals.com/

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Amanjot kaur Saroa 3 Months ago

If the sum of the first 43 terms of an arithmetic progression is 2967, then find the sum of the 11th and the 33rd terms of the same series.

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Varun 3 Months ago

First term = a, Number of terms=n, Difference = d
nth term = a+(n-1)d
11th term = a+10d, 33rd term = a+32d
Sum of 11th & 33rd= 2a+42d = 2(a+21d)=2(22nd term)

Middle term = Total sum/n
43/2 th term = 22nd term = 2967/43 = 69

=>Sum of 11th & 33rd = 2(69) = 138

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G.S.Kantharao 2 Months ago

Sum of first 43 terms in A.P=43(2a+42d)/2=2967
11th term +33rd terms =(a+10d)+(a+32d)=(2a+42d)
43(2a+42d)/2=2967=>(2a+42d)=2967*2/43=138

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