In a certain corporation, there are 2560 male employees and 1440 female employees. It is known that 15% of the male employees have advanced degrees and 25% of the females have advanced degrees. If one of the employees is chosen at random, what is the probability this employee has an advanced degree?
Number of male employess with Adv. degree = 2560*15/100 = 384
Number of female employess with Adv. degree = 1440*25/100 = 360
Total number of employees with adv. degree = 744
A person borrows Rs. 22500 for 3 years at 4.5% p.a. simple interest. He immediately lends it to another person at 7.25 p.a for 3 years. Find his gain in the transaction per year.
An alphanumeric character is randomly selected from following sentence:
"Mathematics is the art of giving the same name to different things"
What is the probability that its an vowel or letter R?
Note: Alphanumeric character means alphabet or number. Space and other characters should be ignored.
In 2020, A would be 8 years older than B who would be eleven times as old as C. Also, the total of the ages of A, B and C in 2019 would be 143 years. What is the average of A and B ages in 2024 ?
OPtion
1) 70 years
2) 71 years
3) 72 years
4) 77 years
5) 76 years
6) 75 years
7) 74 years
8) 78 years
9) 73 years
10)None of these
Solution
Total ages of A+B+C in 2019 = 143
Total ages of A+B+C in 2020 = 143 + 3 = 146 years
In 2020
Let’s assume Age of B be B years
Age of A = B+8
Age of C = B/11
Total age = B + 8 + B + B/11 = 146
Solving 23B/11 = 136
B = 66
A = B+8 = 74
C = 66/11 = 6
In 2024 - i.e. 4 years later
Age of A = 74+4 = 78
Age of B = 66+4 = 70
YEH 25-5-8 DIL 4-9-12 MANGE 13-1-14-7-5 MORE 13-15-18-5
Value of Smallest positioned alphabet in YEH = 5
Value of Smallest positioned alphabet in DIL = 4
Value of Smallest positioned alphabet in MANGE = 1
Value of Smallest positioned alphabet in MORE = 5
Product of all Values of Smallest positioned alphabets = 5*4*1*5 = 100
Similarly the code for TASTE THE THUNDER:
TASTE 20-1-19-20-5
THE 20-8-5
THUNDER 20-8-21-14-4-5-18
Value of Smallest positioned alphabet in TASTE = 1
Value of Smallest positioned alphabet in THE = 5
Value of Smallest positioned alphabet in THUNDER = 4
Product of all Values of Smallest positioned alphabets = 5*4*1 = 20
Lets arrange the letters of UBIQUITOUS alphabetically = BIIOQSTUUU
Words starting with B = 9!/(2!*3!) = 30240
Words starting with I = 9!/(3!) = 60480
Words starting with O = 9!/(2!*3!) = 30240
Words starting with Q = 9!/(2!*3!) = 30240
Words starting with S = 9!/(2!*3!) = 30240
Words starting with T = 9!/(2!*3!) = 30240
Words starting with UBII = 6!/(2!) = 360
Words starting with UBIO = 6!/(2!) = 360
Words starting with UBIQI = 5!/(2!) = 60
Words starting with UBIQO = 5!/(2!) = 60
Words starting with UBIQS = 5!/(2!) = 60
Words starting with UBIQT = 5!/(2!) = 60
Words starting with UBIQUIO = 3! = 6
Words starting with UBIQUIS = 3! = 6
Words starting with UBIQUITOSU = 1
and next word is UBIQUITOUS = 1