M4maths Previous Puzzles

19 Jul 2017 Perfect Squares

How many factors of 878800000 are perfect squares?

OPtion

1) 8
2) 27
3) 18
4) 12
5) 24
6) 16
7) 36
8) 32
9) 48
10) None of these

Solution

878800000 = 2^7* 5^5 * 13^3

Any factor of this number should be of the form 2^a * 5^b * 13^c.

For the factor to be a perfect square a,b,c have to be even.

a can take values 0, 2, 4, 6
b can take values 0, 2, 4
and c can take values 0, 2

Total number of perfect squares = 4 * 3 * 2 = 24

Correct Option: 5 Best Solution (4)

yamini velaga   7 years AGO

878800000 = (2^7) × (5^5) × (13^3)
Any factor of 878800000 can be expressed as (2^a) × ( 5^b) × (13^c)
a,b,c should be even numbers
possibilities for a,b,c are
a -------> 0,2,4,6 ----- 4 possibilities
b--------> 0,2,4 --------3 possibilities
c--------> 0,2 -----------2 possibilities
no.of perfect squares among the factors of 878800000 = 4×3×2 = 24

Like? Yes (9) | No   

G.S.Kantharao   7 years AGO

Given = 878800000
Product of prime factors = (2^7)*(5^5)*(13^3)
Factors which are also perfect squares from the above are= 1,4,16,25,64,100,169,400,625,676,1600,2500,2704,4225,10000,10816,16900,40000,67600,270400,422500,1081600,1690000,6760000 (Total no.24)
Hence the right option is 5👈

Like? Yes | No   

Mukund Manohar   7 years AGO

Factors of 878800000 = 2^7 * 5^5 * 13^3
Values for perfect square = 2^0,2^2,2^4,2^6 = 4 values
Values for perfect square = 5^0,5^2,5^4 = 3 values
Values for perfect square = 13^0,13^2 = 2 values
Total Values = 4*3*2 = 24
24 factors of 878800000 are perfect squares.

Like? Yes | No   

jksdvs   7 years AGO

1000000*13*13 and 26 remains 169 and 100 100 100 forms perfect so there are 4 numbers which forms perfect squares they can be shuffled in 24 ways

Like? Yes | No   

18 Jul 2017 Find the value

If m and n are whole numbers and m^n = 289, what is the value of (m - 14)^(n+2) ?

OPtion

1) 8
2) 9
3) 16
4) 27
5) 32
6) 64
7) 81
8) 128
9) 243
10) None of these

Solution

m^n = 289

We know that 17^2 = 289

Hence we can take m = 17 and n = 2
So (m - 14)^(n+2) = (17-14)^2+2 = 3^4 = 81

Correct Option: 7 Best Solution (42)

SAYAN CHATTERJEE   7 years AGO

289 is the square of 17, hence the m=17, n=2
so, (m-14)^(n+2)
= 3^4
= 81.
Option 7.

Like? Yes | No   

AYAN PAUL   7 years AGO

In the question it is given that m^n = 289 we know that 17^2 = 289 so m=17 and n=2
so (m-14)^(n+2)= 3^4 = 81

Like? Yes | No   

Mukund Manohar   7 years AGO

m^n = 289
=> m^n = 17^2
m=17 and n=2
Value of (m-14)^(n+2)
= (17-14)^(2+2)
= 3^4
= 81

Like? Yes | No   

ganesh chemanchula   7 years AGO

289=(17)^2 therefore m=17 and n=2
Then (17-14)^(2+2)= (3)^4=81

Like? Yes | No   

Shritansh   7 years AGO

Since we have m^n =289
On solving we get m=17,n=2
Therefore value of (m-14)^(n+2)=81

Like? Yes | No   

satish kumar   7 years AGO

by heat & trial m= 17 n=2
solving,(17-14)^2+2
=81

Like? Yes | No   

Poulami Banik   7 years AGO

17^2=289
(17-14)^(2+2)
=3^4
=81

Like? Yes | No   

Ranadip Bhattacharya   7 years AGO

m=17
n=2
putting the formula, the answer is 81.
I.e., option (7)

Like? Yes | No   

jyothi chhabria   7 years AGO

m^n=289=17^2
m=17 n=2
(m-14)^(n+2)=(17-14)^4=3^4=81

Like? Yes | No   

Gokul Krishnan   7 years AGO

m^n=289
17^2=289
(m-n)^(n+2)=(17-14)^(2+2)=81

Like? Yes | No   

Pragya Srivastava   7 years AGO

m^n = 289
m=17 &n = 2
(m-14)^(n+2)= (17-14)^(2+2)
= 3^4= 81

Like? Yes | No   

G.S.Kantharao   7 years AGO

m^n=289=17^2
m=17,n=2
Then (m-14)^(n+2)=(17-14)^(2+2)=3^4=81.
Hence the right option is 7☝

Like? Yes | No   

SOUMYA GOURIPEDDI   7 years AGO

m^n=289
m=17
n=2
by substituting the values,we can get the answer

Like? Yes | No   

Nitish Sinha   7 years AGO

m^n=289
m=17, n=2
17^2=289

Therefore, (m-14)^(n+2)
= (17-14)^(2+2)
= 3^4
= 81

Answer: Option-7

Like? Yes | No   

palak Jain   7 years AGO

m^n=289
m=17
n=2
m-14=3
n+2=4
3^4=81

Like? Yes | No   

Balaji raju   7 years AGO

17^2=289
17-14=3
2+2=4
3^4=81

Like? Yes | No   

Arpan Arora   7 years AGO

let m=17 , n=2
17^2=289

(17-14)^(2+2)=81

Like? Yes | No   

sumanth   7 years AGO

given, m^n=289. By calculations 17^2 is also 289.
so, m is 17 and n is 2.
Hence, (17-14)^(2+2)=81

Like? Yes | No   

Vaibhav Ranpara   7 years AGO

HERE ONLY ONE POSSIBILITY IS POSSIBLE FOR WHOLE NUMBER.
AND THAT IS 17^2
IT MEANS 17*17
THAT'S WHY
M=17 AND N=2
SO,
(M-14^(N+2)=3^4=81

Like? Yes | No   

AKASH KUMAR DAS   7 years AGO

m^n=17^2
therefore m=17 and n=2
so that (17-14)^(2+2)=3^4=81

Like? Yes | No   

yamini velaga   7 years AGO

m^n = 289 ------> m = 17 & n = 2
(m - 14)^(n + 2) = 3^4 = 81

Like? Yes | No   

Anita   7 years AGO

m^n=289=17^2
m=17
n=2
(m-14)^(n+2)= 3^4=81

Like? Yes | No   

Vignesh   7 years AGO

17^2=289
so m=17,n=2
m-14=3
n+2=4
So 3^4 is 81

Like? Yes | No   

Jaimin Raval   7 years AGO

17 square 289 and m 17 n 2 so value of the given data is 3 power 4 81

Like? Yes | No   

Sunitee Garima   7 years AGO

Given,m^n=289
taking log both sides
=>nlogm=log 289
=>nlogm=log(17)^2
=>nlogm=2logm
Equating both sides,we have
n=2 and m=17

Now,(m-14)^(n+2)
Putting values of m and n ,we get answer as 81

Like? Yes | No   

MOHIT KUMAR   7 years AGO

because
m^n=17^2
m=17,n=2
3^4=81

Like? Yes | No   

Pooja Prabhakar Patekar   7 years AGO

sq.root of 289=17,
hence m=17 and n=2
17-14=3 and 2+2=4
3^4=81

Like? Yes | No   

Rahul   7 years AGO

17^2=289
So m=17 and n=2

And put in eq. Gives 81

Like? Yes | No   

THUMMALA VINEESHA   7 years AGO

m^n =17^2
m=17, n=2

3^4=81

Like? Yes | No   

NABA KISHORE PADHY   7 years AGO

M^N=289 means 17^2 M is 17, N is 2

(M-14)^(N+2)=(17-14)^(2+2)=3^4=81

Like? Yes | No   

Pavleen   7 years AGO

287 is the square of 17 ,so m is 17 and n is 2, then solving the equation the answer comes out to be 81

Like? Yes | No   

Souvik Pal   7 years AGO

17^2=289
So,m=17;n=2
By the problem,
(17-14)^(2+2)=3^4=81

Like? Yes | No   

sneha   7 years AGO

m^n=289
17^2=289 hence m=17 and n=2
(m-14)^(n+2)=(17-14)^(2+2)=81

Like? Yes | No   

Anjali   7 years AGO

As m^n is 289 means m must be less 20 and it can only so it can only 3,7,9,13,17,19 now as we see only 17 can divide 289 so
17^2 =289
So (17-14)^(2+2)=81

Like? Yes | No   

chaiethanya   7 years AGO

square of 17 is 289.
so m=17,n=2.

fourth power of 3 is 81

Like? Yes | No   

Harish   7 years AGO

M=17
N=2
->17^2=289
(17-14)^(2+2)=81

Like? Yes | No   

Prem Kumar   7 years AGO

m^n=289=17² ⇒ m=17and n=2
∴ (m-14)^(n+2)=3^4=81

Like? Yes | No   

Rohan   7 years AGO

m power is n=289 and 17 square is 289 so M=19 and N=2.
Put values of m and n in the equation and get the 81 as answer

Like? Yes | No   

Sonu Kumar   7 years AGO

17^2=289
m=17,n=2
So A/c question (m-14)^(n+2)=81 currect answer is 7)81

Like? Yes | No   

priya v   7 years AGO

17^2=289
so we get m,n from them and solve the question

Like? Yes | No   

SHAILEE KUMARI   7 years AGO

17^2=289
m=17,n=2
(17-14)^(2+2)
3^4=81

Like? Yes | No   

Chain Singh Kirar   7 years AGO

(17)^2=289
m=17
n=2
...............
(17-14)^(2+2)=81

Like? Yes | No   

17 Jul 2017 Simple Interest

A sum fetched a total simple interest of Rs. 453 at the rate of 6% p.a. in 5 years. What is the sum?

OPtion

1) Rs 1450
2) Rs 1475
3) Rs 1500
4) Rs 1510
5) Rs 1024
6) Rs 1660
7) Rs 1620
8) Rs 1550
9) Rs 1490
10) None of these

Solution

SI = PRT/100
P= SI*100/RT = 453*100/5*6 = 1510
Option 4)

Correct Option: 4 Best Solution (21)

jyothi chhabria   7 years AGO

SI=ptr/100
453=p×5×6/100
45300/30=p
therefore the sum is 1510 /_
option 4👍

Like? Yes (1) | No   

W J Krishna Teja   7 years AGO

Simple Interest =(P*R*T)/100
Here , SI=453
P=?
R=6
T=5
Substituting values in formula we get 453=(P*6*5)100
That gives P=(453*100)/(6*5)=1510

Like? Yes | No   

Devendra Marghade   7 years AGO

Let the sum be Rs. x, then x*6*5/100 = 453
=> x=1510
Option 4)

Like? Yes | No   

Ravi   7 years AGO

S.I=p×r×t/100
so,453=p×6×5/100
p=1510

Like? Yes | No   

SAYAN CHATTERJEE   7 years AGO

SI.= X*6*5/100= 453
SO, sum=X= 1510
Option 4.

Like? Yes | No   

ALOKENDRA PAL   7 years AGO

prt/100=453,
here r=6,t=5,need to determine p
so,p=45300/(5*6)

Like? Yes | No   

AYAN PAUL   7 years AGO

We know in case of simple interest the formula is :
Interest = (P*r*t)/100
where P = Principal , r= rate of interest and t = time
So from the question if we put the values in the above equation the equation becomes
453 = (P*6*5)/100
by solving it we can get P = Rs. 1510

Like? Yes | No   

G.S.Kantharao   7 years AGO

Principal=100I/RT =100*453/6*5=₹1510
Hence the Right option is 4.👈

Like? Yes | No   

Pranab Thakuria   7 years AGO

SI = PRT/100
=> 453=PRT/100
=> P= (453*100)/(6*5)
=> P= 1510

Like? Yes | No   

Nitish Sinha   7 years AGO

S.I =453
R=6%
T=5 yrs
Therefore ,
P=S.I*100/R*T
P=453*100/6*5
P=1510

Answer: Option 4

Like? Yes | No   

santosh   7 years AGO

pqr/100=453
p=sum
q=5
r=6

Like? Yes | No   

ramakrishnateja   7 years AGO

given S.I=Rs. 453/-
we know that S.I=PTR/100 which gives 453=(p*5*6)/100
(453*100)/30=p
p=1510/-

Like? Yes | No   

AMAN Sinha   7 years AGO

simple interest formula is used
si=p*r*t/100
put values n find P
ans is 1510

Like? Yes | No   

aribandi sridevi   7 years AGO

si=ptr/100
si=453,p=?,r=6perannum,t=5yrs
p=453*100/6*5=1510

Like? Yes | No   

yamini velaga   7 years AGO

let the amount fetched be `x`
rate of interest p.a. = 6% = 0.06
amount of total interest for 5 years = 453
x × 0.06 × 5 = 453
x = 1510 rs

Like? Yes | No   

Pragya Srivastava   7 years AGO

SI =( P* R*T )/100
453= (P* 6*5)/100
P =( 453*100)/ (6*5 )
P = 1510

Like? Yes | No   

mayank   7 years AGO

caluale the si of each year and then by via percentage given find value

Like? Yes | No   

madanpal vishwakarma    7 years AGO

let the amount is x than as per question

453= x*6*5/100
x= (453*100)/(6*5)
x= 1510 RS

Like? Yes | No   

Ranadip Bhattacharya   7 years AGO

(P*t*r)/100=453
P=453*100/5*6
P=1510
I.e., option (4)

Like? Yes | No   

YAZHINI RANGARAJ   7 years AGO

s.i= pnr/100
given
s.i=453
n=5
r=6
453=(p*5*6)/100
p=(453*10)/3
p=1510

Like? Yes | No   

palla anjali   7 years AGO

SI=453
Sum=p=?
rate=6%
time=5years
formula:
SI=(PTR)/100
P=(SI*100)/(R*T)
P=(453*100)/(6*5)
=1510rps

Like? Yes | No   

14 Jul 2017 Discount

The marked price of a shirt is Rs.1250. A shopkeeper offers 10% discount on this shirt and then again offers 20% discount on the new price, and then and then again offers 30% discount on the new price . How much will you have to pay, finally?

OPtion

1) 900
2) 550
3) 500
4) 590
5) 725
6) 650
7) 625
8) 630
9) 700
10) None of these

Solution

Price after 1st Discount = 1250*90/100 = 1125
Price after 2nd Discount = 1125*80/100 = 900
Price after 3rd discount = 900*70/100 = 630

Hence Option 8)

Correct Option: 8 Best Solution (46)

AYAN PAUL   7 years AGO

Marked Price of the Shirt = Rs. 1250
Then the shopkeeper offers 10% 20% & 30% discount respectively on marked price
So the final selling price of the shirt will be =
(1250*90*80*70)/1000000 = Rs. 630

Like? Yes (3) | No   

G.S.Kantharao   7 years AGO

Marked Price =₹.1250
Successive discounts are = 10%,20%,30%
Selling Price = 1250*0.9*0.8*0.7=₹630
Hence the Right option is 8.👈

Like? Yes (3) | No (1)  

palak Jain   7 years AGO

10% 1250=125
Gives 1125
20 % 1125=225
Gives 900
30% 900=270
Gives 630

Like? Yes (1) | No   

W J Krishna Teja   7 years AGO

Marked price=1250,
First Discount=10%, Amount payable=90% of Marked Price
2nd Discount= 20%, Amount Payable=80% of new Price,
3rd Discount= 30% of new Price
So amount payable= 70% of new Price
So Total Amount payable=70% of (80% of(90% of 1250))=70%of(80%of1125)=70%of900=630

Like? Yes | No   

Mukund Manohar   7 years AGO

Equivalent discount of 10%,20% and 30% = 49.6%
49.6% of 1250 = 620
Final amount to be paid = 1250 - 620 = Rs 630

Like? Yes | No   

Shritansh   7 years AGO

Since on first discount we get m.p of shirt= 1125
After that 20% we get m.p of shirt =900
After 30% we get m.p of shirt= 630

Like? Yes | No   

SAYAN CHATTERJEE   7 years AGO

Price to pay: 1250*9/10*8/10*7/10
= 630.
Option 8.

Like? Yes | No   

Rahul   7 years AGO

10% of 1250 becomes 1125
20%of1125becomes 900
30%of900becomes 630

Like? Yes | No   

Mounika   7 years AGO

Price after 1st discount = 1250*90/100=1125
Price after 2nd discount =1125*80/100=900
Price after 3rd discount =900*70/100=630

Hence option 8

Like? Yes | No   

Karuna   7 years AGO

1250*0.9=1125
1125*0.8=900
900*0.7=630
hence, option 8 is correct.

Like? Yes | No   

Vanga Bhagya anantha Naga lakshmi   7 years AGO

10%of 1250 is 125. 1250-125=1125
20%of 1125 is 225.1125-225=900
30%of 900 is 270.900-270=630. finally 630 answer

Like? Yes | No   

abhi   7 years AGO

total discount =49.6% then 1250 of49.6%=620 hence fianly payable balance is 630

Like? Yes | No   

Kamalpreet Singh   7 years AGO

As we know that if the market price is 'M' and discount is 'D1' then amount payable after the discount will be=P1=
M*(100-D1)/100
As the discount is given multiple times so next time 'M' will be replaced by the new price after first discount i.e. 'P1'
so amount after D2 is:
=P2=P1*(100-D2)/100=M*((100-D1)/100)*((100-D2)/100)
similarly we get for D3 as:
M*((100-D)/100)*((100-D2)/100)*((100-D3)/100)

Here M=1250,D1=10%,D2=20%,D3=30%

amount to be paid
=1250*((100-10)/100)*((100-20)/100)*((100-30)/100)
=1250*(90/100)*(80/100)*(70/100)
=1250*0.9*0.8*0.7
=630

Option 8)

Like? Yes | No   

Poulami Banik   7 years AGO

1250 10% discount = 1125
1125 20% discount = 900
900 30% discount= 630
So the answer is 630

Like? Yes | No   

Chandra prakash sharma   7 years AGO

1250--10%=125 new price=1125
1125--20%=225 new price=900
900--30%=270 new price=630
So my ans 8-630

Like? Yes | No   

Sahaya Rishwan   7 years AGO

10% discount is125
20% discount on the new price is 225
30% discount on after new price is 270

Like? Yes | No   

Jaimin Raval   7 years AGO

1250 discount 10 percent 1250-125=1125 now 20 percent discount. 1125-225= 900 now. 30 discount. 900-270= 630

Like? Yes | No   

Pragya Srivastava   7 years AGO

First discount- 1250 - (1250 of 10% )= 1125
Second discount - 1125 - (1125 of 20%)= 900
Third discount - 900 -(900 of 30 % )= 630

Like? Yes | No   

Gokul Krishnan   7 years AGO

disc on Rs 1250 with 10%=Rs.1125
again disc on Rs 1125 with 20%=Rs.900
again with 30% on Rs 900=Rs.630

Like? Yes | No   

karthy   7 years AGO

i)1250 *10/100=125;
1250-125=1125
ii)1125*20/100=225
1125-225=900
iii)900*30/100=270
900-270=630
ans=630

Like? Yes | No   

suman   7 years AGO

10% of 1250 is 125 is first disount
so new price is 1125
20% discount on 1125 is 225
so new price is 900
30 % discount on 900 is 270
so final price is 630

Like? Yes | No   

Hemanth   7 years AGO

After deducting 10% discount on 1250 new price will be 1125. Again deducing 20% discount on 1125 so new price will be 900. And again 30% discount on 900 will be 270. So finally price will be 630

Like? Yes | No   

THUMMALA VINEESHA   7 years AGO

cost is 1250
10% of 1250 = 125
cost will be 1125
20% of 1125 =225
cost will be 900
30% of 900 = 270
cost will be 630

ans is 630

Like? Yes | No   

Prudhvi Kumar Jellu   7 years AGO

initial 10% discount means price reduces to 1125, then 20% discount on resultant price means new price becomes 900,he again offers 30% discount on new price . So finnaly the price becomes 630 which we have to pay.

Like? Yes | No   

Renu   7 years AGO

1250*90/100=1125 for 10%
1125*80/100=900 for 20%
900*70/100=630 for 30%

Like? Yes | No   

Vishalakshi Tiwari   7 years AGO

10% of 1250=125
selling price=1250-125=1125
20% of 1125=225
new selling price=1125-225=900
30% of 900=270
final selling price=900-270=630

Like? Yes | No   

Vaibhav Ranpara   7 years AGO

M.P.=1250
1.
1250*0.90=1125
2.
1125*.80=900
3.
900*0.70=630 FINAL PRICE

Like? Yes | No   

Deepthi Sarvani   7 years AGO

10%of1250=125
1250-125=1125
20%of1125=225
1125-225=900
30%of900=270
900-270=630
finally he has to pay Rs 630.

Like? Yes | No   

Haraprabhakar   7 years AGO

10% of 1250=125
1250-125=1125
20% of 1125=225
1125-225=900
30% of 900=270
900-270=630

Like? Yes | No   

aparna padakanti   7 years AGO

10% of 1250 is 125 discount and again 20 % on new then it is 225 and 30 % then it is 270 overall it has pay 630

Like? Yes | No   

madanpal vishwakarma    7 years AGO

The original price of shirt=1250
10 % discount = 1250 -(1250*10)/100 =1125

now 20 % on previous price =20 % of 1125 =1125-225=900

now 30% discount on 900=270

so final price =900-270 =630

Like? Yes | No   

NABA KISHORE PADHY   7 years AGO

consecutive discount of 10%, 20% & 30 % means a total of 49.6% discount
net you have to pay = 1250*(100-49.6)=1250*50.4%=630

Like? Yes | No   

jay   7 years AGO

1250 discount is 125....1125
than 225 than 900 .....than 270 ...630

Like? Yes | No   

Vasanth   7 years AGO

After applying the discount of the respective amount we will get this solution

Like? Yes | No   

Nikhil Tyagi   7 years AGO

Because first 10% discount on 1250
Therefore 10÷100×1250=125
1250-125=1125
New price is 1125
Again 20% discount on new price which is 1125

20÷100×1125=225
Therefore 1125-225=900 which is new price
Again 30% discount on new price which is 900
Therefore 30÷100×900=270
New price will be 900-270=630

Like? Yes | No   

vishal umrao   7 years AGO

first shopkeeper give 10% discount on mrp after that the prise of shirt will 1125 and then he offers 20% discount in new prise so then prise will 900 and then he offers 30% discount in new prise and the final prise will be 630.

Like? Yes | No   

p.pavan ravi varma   7 years AGO

after getting discount for that shirt we should again do discount and repeats

Like? Yes | No   

shettyshambhavi   7 years AGO

10/100*1250=125
1250-125=1125
20% 1125=225
1125-225=900
30% 900=270
900-270=630

Like? Yes | No   

Adarsh pandey   7 years AGO

1250 10% = 125 i.e 1250-125 = 1125
1125 20% = 225 i.e 1125-225 = 900
900 30% = 270 i.e 900- 270 = 630
so rs 630 you have to pay

Like? Yes | No   

Meena   7 years AGO

1250*(10/100)=125
1250-125=1125
1125*(20/100)=225
1125-225=900
900*(30/100)=270
900-270=630

Like? Yes | No   

Nithilam   7 years AGO

sp-1250
discount 10%
10/100*1250
did =125
rem amount 1125
then 20/100*1125
dis 225
rem 900
then 30% discount
30/100*900
dis 270
remaining 630
answer 630

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soumya   7 years AGO

10% of 1250 is 125 so the cost reduced to 1125 the 20%of 225 so the cost again reduced to 900 then again 30% of 900 is 270 so the final cost of the shirt is 630.

Like? Yes | No   

imran   7 years AGO

10% of 1250=125
So new sp=1125
20% of 1125=112.5*2=225
So new sp=1125-225=900
30% of 900=90*3=270
So new sp =900-270=630

Like? Yes | No   

ajit bharti   7 years AGO

marked price=1250/-
after 10% discount, new price will be=1250-(10/100*1250)=1125/-
again 20% off on new price=1125-(20/100*1125)=900/-
again 30% discount on new price=900-(30/100*900)=630/-

Like? Yes | No   

ANANDA PRIYA T.R   7 years AGO

Rs1250 with 10% discount it becomes Rs1125
Rs1125 with 20%discount it becomes Rs 900
Rs900 with 30% discount it becomes Rs 630

Like? Yes | No   

satish kumar   7 years AGO

1250*90/100*80/100*70/100=630

Like? Yes | No (1)  

13 Jul 2017 Age

A is 2 years older than B who is thrice as old as C. The total of the ages of A, B and C is 51. What is the product of their ages?

OPtion

1) 3360
2) 3381
3) 3036
4) 2760
5) 3696
6) 3318
7) 3630
8) 2670
9) 3618
10)None of these

Solution

Let’s assume Age of B be B years
Age of A = B+2
Age of C = B/3

Total age = B + 2 + B + B/3 = 51
Solving 7B/3 = 49
B = 21
C = B/3 = 21/3 = 7 years
A = 21+2 = 23
Product = 21*23*7 = 3381

Option 2)

Correct Option: 2 Best Solution (44)

SAYAN CHATTERJEE   7 years AGO

A=B+2
B=3C
SO, A+B+C=3C+2+3C+C=7C+2=51
=> C=7
SO, B=7*3=21
& A= 21+2=23
SO, A*B*C= 7*21*23=3381
Option 2.

Like? Yes | No   

Sukanya Ray Chowdhury    7 years AGO

3c+2+3c+c=51
c=7
b=21
a=23
abc=23×21×7=3381

Like? Yes | No   

G.S.Kantharao   7 years AGO

Let the ages are (3x+2),(3x),(x)
(3x+2)+(3x)+(x)=7x+2=51
X =(51-2)/7=49/7=7
Their ages are=23,21,7yrs.
Product of their ages=3381yrs.
Hence the right option is 2.

Like? Yes | No   

Poulami Banik   7 years AGO

Let age of C=x
Age of B=3x
Age of A= 3x+2
So,
(3x+2)+3x+x=51
x=7
So C=7,B=21,A=23
Product of their age....
7*21*23=3381

Like? Yes | No   

Mukund Manohar   7 years AGO

Let the age of C be x years
Age of B = 3x years
Age of A = 3x+2 years
ATQ,
3x+2 + 3x + x = 51
=> 7x = 49
x = 7
C = 7 years
B = 21 years
A = 23 years
Product of their ages = 7*21*23 = 3381

Like? Yes | No   

ajit bharti   7 years AGO

Let the age of C,B and A be x,3x,3x+2.
According to question sum of ages equals to 51.
i.e. 7x+2=51.
Therefore x=7.
Now the ages will be.
C=x=7years
B=3x=21years
A=3x+2=23years
So, the product of ages will be 7*21*23=3381

Like? Yes | No   

Gokul Krishnan   7 years AGO

Given c=x,b=3x,a=2+3x
total=51
x=7
hence product is=3381

Like? Yes | No   

Pavleen   7 years AGO

let C age be x. then B age will be 3x and A age 2+3x.the sum of ages of A,B and C is 51.therefore after solving the equation we get all the ages.

Like? Yes | No   

aparna padakanti   7 years AGO

c=c b=3c a=3c+2 a+b+c=51 by solving we get c=7b=21a=23 abc=3381

Like? Yes | No   

Mounika   7 years AGO

A=2+B --------(1)
B=3C ----------(2)
And A+B+C=51 -----(3)
Solving equations (1),(2)&(3) ; we get
A=23, B=21 and C=7

Product of their ages is ABC = 23*21*7=3381

Like? Yes | No   

Vishalakshi Tiwari   7 years AGO

A=B+2,B=3C
A+B+C=51
ON SOLVING,
A=23 Years, B=21 Years, C=7 Years
Hence,
A×B×C=23×21×7=3381

Like? Yes | No   

Nitish Sinha   7 years AGO

Let the age of C be x years,
therefore B=3x and A= 3x+2 years respectively
Now,
(3x+2)+3x+x=51
7x+2=51
x=7
Putting the value x we get,
Age of A= 3x+2=23
Age of B= 3x= 21
Age of C= x=7

Therefore product of their ages are:
23*21*7= 3381
Answer : Option 2

Like? Yes | No   

Deepika   7 years AGO

A=b+2
B=3c
A+b+c=51
B+2+b+b/3=51
3b+6+3b+b=153
7b=147
B=21
C=7
A=23
A*b*c=3381

Like? Yes | No   

sameer   7 years AGO

X+3x+3x+2=51 where we get x=7 so the respective ages are 7,21,23 and their product comes to be 3381

Like? Yes | No   

Harshita   7 years AGO

Let the age of C be x, so age of B=3x and that of A is 3x+2.
so x+3x+3x+2=51
7x+2=51
x=7
so age of C=7,
age of B= 21
age of A= 23
A*B*C=3381.

Like? Yes | No   

prashant   7 years AGO

eqn 1. A=2+B
eqn 2. B=3C
eqn 3. A+B+C=51
putting B=3C from eqn2 in eqn 1,
we get A=2+3C(eqn. 4)
now putting the value of eqn 2 and eqn 4 in eqn 3
We'll get C=7 so B=21 and A=23
and their products will be 7×23×21=3381

Like? Yes | No   

Ravi   7 years AGO

let c=x,then b=3x and a=3x+2
now a+b+c=51(given) then x=7
so a=23,b=21 and c=7 so product will be
23×21×7=3381

Like? Yes | No   

Deepthi Sarvani   7 years AGO

A=B+2
B=3C
A+B+C=51
B+2+B+B/3=51
7B=147=>B=21
A=21+2=23
C=21/3=7
A*B*C=21*23*7
=3381

Like? Yes | No   

abhi   7 years AGO

A=B+2 ,C=B/3 then a+b+c=51 then b=21 A=23 nd. C =7 product of A B ND C =3381

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THUMMALA VINEESHA   7 years AGO

a=b+2
b=3c
a+b+c=51
3c+2+3c+c=51
7c=49
c=7
b=21
c=23
a*b*c=21*23*7=3381

Like? Yes | No   

manasa   7 years AGO

a is 2 years older than B then , A=B+2
B is thrice as C then, 3C=B then A=3C+2
sum of their age is 51
A+B+C=51
3C+2+3C+C= 51 then C=7,B=21,A=23.
then 7*21*23=3381

Like? Yes | No   

Ranadip Bhattacharya   7 years AGO

A+B+C=51
A=23
B=23-2=21
C=51-(23+21)=7
A*B*C=23*21*7=3381
Hence, Option (2)

Like? Yes | No   

Pragya Srivastava   7 years AGO

Let C age =x , B age = 3x , A age = 3x +2
total of their age is 51
x +3x +(3x+2)=51
so x = 7
A =3*7 + 2= 23
B= 3*7=21
C=7
Product of their age = 23*21*7 = 3381

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AMAN Sinha   7 years AGO

Acc to ques
A=B+2. eqn -1
B=3C. eqn -2
from eqn 1and 2 we got 3 eqn
A=3C+2
A+B+C=51. eqn 4
put value of eqn 2 n 3 on 4 we got the value of C i.e 7
put the value of c in 2 n 3 eqn we got value of A B C
A=23
B=21
c=7
product them n we got 3381

Like? Yes | No   

vinitmendapara   7 years AGO

suppose
C's age is x
so B's age is 3x
so B's age is 3x+2

Sum of all = 51
3x+2 + 3x + x = 51
7x = 49
x = 7

A's age 23
B's age 21
C's age 7

23*21*7 = 3381

so option B

Like? Yes | No   

ramakrishnateja   7 years AGO

From thegiven conditions A=B+2, B=3C, A+B+C=51.
B+2+B+(B/3)=51, 7B+6=51*3=153
7B=153-6=147 which means B=21.
A=B+2 which means A=23, c=B/3, c=21/3=7.

A*B*C=21*23*7=3381.

Like? Yes | No   

Hari Priya   7 years AGO

let c be x.
so x+3x+3x+2=51
x=7
substitute and find the product. ans 3381

Like? Yes | No   

Gaurang Rathod   7 years AGO

let say, Age of C is x, so Age of B would be 3x.and age of A would be 3x+2.Now Total of their age is 51 and by solving Equation we get the value of X equals to 7.Now Ages of A, B and C is 23,21,7 and product of these numbers are 3381.

Like? Yes | No   

Nabendu   7 years AGO

A. x+2
B. x
C. x/3
Now x+2+x+(x/3)=51
So,x=21
So, Products of Ages are =(23*21*7)=3381

Like? Yes | No   

yamini velaga   7 years AGO

let the age of `C` be `x` . Then age of `B` will be ` 3x` & the age of `A` will be ` 3x + 3`.
sum of ages = 51 ===》 x+ 3x +( 3x+2) = 51
-------> x = 7
product of ages = x. 3x. (3x+2) = 7×21×23 = 3381

Like? Yes | No   

SOUMI CHAKRABORTY   7 years AGO

if age of C is x, then age of B is 3x and age of A is 3x+2.. solving that we find the individual ages and then the product

Like? Yes | No   

SMRITHI V   7 years AGO

A=(B+2);B=3C=>C =B/3.
A+B+C=51
(B+2+B+B/3)=51. On Solving, A=23,B=21,C=7. 23×21×7=3381

Like? Yes | No   

Jaimin Raval   7 years AGO

a is 2 years older than b also b is thrice old as c so equations a=b+2. and b=3c. sum of their ages is 51 c=c b=3c and. a=3c+2 so 7c+2=51 so c =7. and a=23 b=21 product of this is 23*21*7= 3381

Like? Yes | No   

Ruchi kumari   7 years AGO

Let c=x, b=3x, a=3x+2
Given that, a+b+c=51
Then, x= 7 a=23,b=21,c=7
Product of these = 3381

Like? Yes | No   

Kalidindi Sasidhar   7 years AGO

A=3C+2, B=3C, C=C
A+B+C=51---> 7C+2=51----->7C=49--->C=7,B=21,A=23
A*B*C=23*21*7=3381

Like? Yes | No   

sandeep mattagunja   7 years AGO

A=(3X+2)(since a is 2 years older that b)
B=3X(since b is 3 times older than c)
C=X
now by adding
A+B+C=(3X+2)+3X+X=51(since total is 51)
7X+2=51
7X=49
X=7(result is c age)
by substituting the value of x we get
A=(3(7)+2)=23
B=3(7)=21
C=7
product of ages=23*21*7=3381

Like? Yes | No   

abhishek   7 years AGO

Let C's age is x.
Then B's age is 3x .
And A's age is 3x + 2.
Therefore total age of A , B , C is 51 as per given question.
x+3x+3x+2=51
7x+2=51
x=49.

Now product of A , B , C is 7*3*7*(3*7+2)=3381
Therefore option 2)

Like? Yes | No   

Ashok   7 years AGO

A+B+C=51
A=B+2
B=3C
then, A=23,B=21,C=7
23*21*7=3381

Like? Yes | No   

Vaibhav Ranpara   7 years AGO

A+B+C=51.......(1)
A=B+2......(2)
B=3C.....(3)

A=3C+2
NOW PUT ALL EQUATION IN THE FORM OF C IN EQ.1
SO,
C=7
B=3(C)=21
A=B+2=23
A*B*C=21*23*7=3381

Like? Yes | No   

Vuppala Sathvik   7 years AGO

A+2=B
B=3C
A+B+C=51
B-2+B+(B/3)=51
(7B/3)=49
B=21
A=23
C=7
ABC=23*21*7=3381

Like? Yes | No   

Mandava saipragna   7 years AGO

a=2+b
b=3c
a+b+c=51
a+(a-2)+((a-2)/3)=51
2a+a/3=51+2+2/3
7a=53*3+2
a=161/7=23
=23*21*7

Like? Yes | No   

Sarwar Shams   7 years AGO

let c be x ,b becomes 3x and A becomes 3x+2 , A+B+C=51 solving this we get x=7 -> c=7,b=21 and a=23 so product is 23x21x7=3381

Like? Yes | No   

soumya   7 years AGO

let take A,B,C as 3 person.let take the age of b is x so the age of a becomes x+2 and the age of c is x/3.By solving these we get the age of A=23,B=21,C=7.

Like? Yes | No   

krishameera kadalayil   7 years AGO

b+2=a
b=3c
a+b+c=51 and solving we get b=21 so a=23 c=7 and a*b*c=3381

Like? Yes | No   

12 Jul 2017 Radius and Volume

2 solid spheres of radius 3 m, 3 solid cylinder of radius 2 m, height 3 meter and 2 solid cones of radius 2 m, height 4 m are melted to form a bigger solid sphere. What is the radius of this bigger solid sphere in meters?

OPtion

1) 4.17
2) 4.12
3) 4.46
4) 4.01
5) 4.87
6) 4.81
7) 3.73
8) 3.66
9) 3.58
10)3.51

Solution

Volume of 2 smaller sphere's = 2*(4/3)*Pi*r1^3
Volume of 3 Cylinder = 3*(Pi*r2^2*h1)
Volume of 2 Cones = 2*(1/3)*Pi*r2^2*h2
Volume of Larger Sphere = (4/3)*Pi*R^3
Here r1=3m, r2=2m, h1=3m, h2=4m, and R=?
Volume of Larger Sphere = Volume of 2 smaller sphere's + Volume of 3 Cylinders + Volume of 2 Cones
(4/3)*Pi*R^3 = 2*(4/3)*Pi*r1^3 + 3*P1*r2^2*h1 + 2*(1/3)*Pi*r2^2*h2
=> 4/3*R^3 = (8/3)*27 + 36 + 32/3
=> R^3 = 89
R = 89^(1/3) =4.46 m

Correct Option: 3 Best Solution (11)

Mukund Manohar   7 years AGO

Volume of bigger solid sphere
= (2*113.1) + (3*37.7) + (2*16.76)
= 226.2 + 113.1 + 33.52
= 372.82 m^3
Radius of the bigger solid sphere = cube root(88.97)
= 4.46 m

Like? Yes | No   

SAYAN CHATTERJEE   7 years AGO

(2*4/3*3.14*3^3+3*3.14*2^2*3+2*1/3*3.14*2^2*4)= 4/3*3.14*R^3
hence, R= 4.46.
Option 3.

Like? Yes | No   

Himanshu porwal   7 years AGO

4/3*3.14(54+27+8)=4/3*3.14*r^3
89=r^3
r=(89)^1/3
r=4.46

Like? Yes | No   

AMAN Sinha   7 years AGO

first of all compute the volume of all shapes
vol of spere 4/3pie r^3
cyclinder= pie r^2h
cone =1/3 of cylinder
we add all volume.
total volume is 356/3 pie
now compute the radius using the formula of vol of sphere
radius is 4.46

Like? Yes | No   

ALOKENDRA PAL   7 years AGO

total volume=(36π+72π+32/3π)
then let radius of new sphere is r
so volume is 4/3πr^3=total volume above
so, r=4.46

Like? Yes | No   

Gokul Krishnan   7 years AGO

volume of (2 sphere+3 cylinder+2 cone)=volume of big sphere
on solving, 89=r^3
R=4.46 m

Like? Yes | No   

Nabendu   7 years AGO

2(4π3^3/3)+3(π2^2*3)+2(1*π*2^2*4)=4π r^3/3
So,r^3=89. => r=4.46

Like? Yes | No   

somannagari bhargavi   7 years AGO

calculate volume of everything and add then euating it to the volume of the sphere

Like? Yes | No   

Rahul   7 years AGO

Sum of all given object volume = volume of bigger volume

Like? Yes | No   

ajit bharti   7 years AGO

vol. of new sphare=2(vol. of old sphare)+2(vol. of cone)+3(vol. of cyliender)
4/3*pi*r^3=pi*(356/3)
therefore r^3=cube root of 89
r=4.46

Like? Yes | No   

Shritansh   7 years AGO

Since volume of bigger sphere =89
Therefore 4/3πr ^3 = 89
Hence radius r= 4.46

Like? Yes | No   

11 Jul 2017 Decode

If
26+64 = 801,
32+48 = 701 and
43+57 = 901

Then what is the value of:
67+32 = ?

OPtion

1) 601
2) 201
3) 701
4) 801
5) 1101
6) 101
7) 1001
8) 301
9) 401
10) None of these

Solution

26+64 => Reverse(Reverse (26) + Reverse(64)) = Reverse (62+46) = Reverse (108) = 801
Similarly 32+48 = Reverse(23+84) = Reverse (107) = 701 and
43+57 = Reverse(34+75) = Reverse(109) = 901

So 67+32 = Reverse (76+23) = 99

Correct Option: 10 Best Solution (27)

Mukund Manohar   7 years AGO

26 + 64 = 62 + 46 (Reverse the digits) = 108 = 801 (Reverse the digits of the sum also)
Similarly,
32 + 48 = 23 + 84 = 107 = 701
43 + 57 = 34 + 75 = 109 = 901
67 + 32 = 76 + 23 = 99 = 99

Like? Yes (1) | No   

C. B. HARITHA   7 years AGO

(6+2=8,6+4=10,in this reverse the value of 10=01)so,26+64=801
67+32=(6+3=9,7+2=9)so the ans is 99,but this value is not there, so ans option 10

Like? Yes (1) | No   

Siva Subramanian V S   7 years AGO

26+64=801
Add the first digits of both the numbers
2+6=8
Now add the second digits and reverse them back
6+4=10 when reversed becomes 01
Similarly for the other ones and for the question 67+32 it should come as 99 which is not there in any of the options. So none of these.

Like? Yes | No   

G.S.Kantharao   7 years AGO

26+64=(2+6)(Inverse of 6+4)=801
32+48=(3+4)(Inverse of 2+8)=701
43+57=(4+5)(Inverse of 7+3)=901
67+32=(6+3)(Inverse of 7+2)
=909
Hence my choice is 10.

Like? Yes | No   

Mathangi   7 years AGO

take the number in ten's position and add them i.e from 26 and 64 take 2+6=8. Then take the numbers in unit digit add and then reverse, i.e from 26 and 64 take 6+4=10 and reverse =01. so the number is 801. And 32+48 is 3+4 and reverse of 8+2 so answer is 701. Similarly, 67+32 is 6+3=9 and 7+2=09 and reverse is 90. so answer is 990.

Like? Yes | No   

jyothsna devi   7 years AGO

26+64=(6+2)(6+4=10:01)=801
32+48=(3+4)(8+2=10:01)=701
43+57=(4+5)(3+7=10:01)=901
67+32=(6+3)(7+2=9:90)=990

Like? Yes | No   

lavanya   7 years AGO

in this last digit is added and interchanged i.e last two digits and add tens place

Like? Yes | No   

Sai Naresh Buddi   7 years AGO

26+64= 2+6 and reverse of 6+4
ie 801...
similarly 32+48=701 and
43+57=901......
by above procedure.....the value of
67+32 =99

Like? Yes | No   

reshma   7 years AGO

in 26+64=801;2+6=8&6+4=10 in reverse
32+48=701;3+4=7&2+8=10 in reverse
similarly 43+57=901
hence 67+32 should be 99..so none of these

Like? Yes | No   

mukesh thakur   7 years AGO

67+32=990 ,6+3=9 and 7+2=09
reverse writing of 09
so,answer is 990

Like? Yes | No   

Vaibhav Ranpara   7 years AGO

1.
26+64=801
2nd digit+4th digit=10 and 1st digit+3rd digit=8
now combination of both term 108 and reverse of that number 801.
2.32+48=701
2nd digit+4th digit=10 and 1st digit +3rd digit=7
now combination of both term 107
and reverse of that no. 701
that's how
67+32=99(which is not given)

Like? Yes | No   

Muthubhavani S   7 years AGO

26+64=801,first digit is 2+6=8 2nd digit is reverse of 6+4 so answer is 801.32+48=701 1st digit=3+4=7 2nd digit=reverse of 2+8.Now 67+32=? 1st digit=6+3=9 2nd digit=reverse of 7+2 so answer is 99.

Like? Yes | No   

G.Logesh Kumar   7 years AGO

26+64=,(2+6)=8,(6+4)=10(print reverse) then 801.
32+48=,(3+4)=7,(2+8)=10(print reverse), than 701
43+57=,(4+5)=9,(3+7)=10(print reverse),then 901 that's way
67+32=,(6+3)=9,(7+2)=9 then 99

Like? Yes | No   

PARVEZ ALAM   7 years AGO

units place digit are added first then altered and tens place is simply added.the correct ans is 99

Like? Yes | No   

Jaimin Raval   7 years AGO

26 +64 taking tens place addition we get 8 and then addition of unit digit is ten written in reverse order.for 67+32 no option satisfying this condition

Like? Yes | No   

sushant kumar   7 years AGO

26+64=801 so first we add 2+6=8 then we add 6+4=10 so reverse it 01

Like? Yes | No   

Raji Baskar   7 years AGO

reverse numbers and add,
so
62+46=108=>> 801
23+84=107=>>701
like wise

76+23=99=>> 99

so none of these is answer

Like? Yes | No   

vaisunavee   7 years AGO

in 26 and 64
adding one's place :6+4=10
interchanging the digits to 01
adding the tens place: 2+6=8
totally it is: 801
so for 67+32=990

Like? Yes | No   

sirisha   7 years AGO

in the given problem,the result is obtained by adding the last digit of the second number and the last digit of the first number.
similarly,for the given equation the answer is obtained by adding the digits(2+7)=9
so the correct option will be 10

Like? Yes | No   

Rakshandha   7 years AGO

2+6=8
6+4=10
26+64=801
6+3=9
7+2=9
ans 99

Like? Yes | No   

Nikhith Sannidhi   7 years AGO

add the tens place and multiply by 100. Let this answer be 'x'
add the units place and obtain the answer in 2-digit format(like if you get 9, put it as 09). Then, reverse this sum and add it to x to get the final answer.

example:
26+64:
x=(2+6)*100=800
6+4=10...after reverse 01
answer=800+01=801

67+32:
x=(6+3)*100=900
7+2=09...after reverse:90
answer=900+90=990.
Since there is no option, it is "none of these"

Like? Yes | No   

pankaj bhardwaj   7 years AGO

26+64=801...........add the tens digit 6+4=10 reverse it 01 and then add the ones place digit 6+2=8 ...combine the both 801
thats y answer is 67+32=99

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navdeep jain   7 years AGO

26+64=2+6=8, 6+4=10/01
801
as same as

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susmit   7 years AGO

First Digit is addition of the first digits of the numbers.
Second and third digit combined is the reverse of the addition of the second digits of the number.
For e.g. : 1) 2 + 6 = 8, 6 + 4 = 10.
So, 8 and reverse of 10, that is 801.
2) 3 + 4 = 7, 8 +2 = 10.
7 and reverse of 10, i.e. 701.
3) 4 + 5 = 9, 3 + 7 =10
9 and reverse of 10, i.e. 901.
So for, 67 + 32 -->
6 + 3 = 9, 7 + 2 = 09
so 9 and reverse of '09',
answer in 990.
Hence None Of These.

Like? Yes | No (1)  

SAYAN CHATTERJEE   7 years AGO

26+64= 801 (1ST DIGIT= 2+6. NEXT TWO DIGIT= REVERSE OF 6+4=10)=01
32+48= 701 (1ST DIGIT = 3+4=7. NEXT TWO DIGIT = REVERSE OF 2+8=10)=01
Answer= 67+32
1st digit= 6+3=9
2nd digit= reverse of 7+2=09=90
=990
Option 10.

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somannagari bhargavi   7 years AGO

32+48=701-->32+48=(80)*10-99;
similarly for other clues.Hence the answer is 67+32=99*10-99=891

Like? Yes | No (1)  

Hari Priya   7 years AGO

The series operation is 6+4=10. This answer is reversed. That is 01. Then 2+6=8. So the answer is 801. So when we apply in our problem, the answer should be 67+32=99. So answer is none of these.

Like? Yes | No (1)  

10 Jul 2017 Profit and Loss

When an item is sold for Rs. 29,050, the owner loses 17%. At what price should that plot be sold to get a gain of 27 % ?

OPtion

1) 48600
2) 45000
3) 43000
4) 40000
5) 44450
6) 42600
7) 44900
8) 48000
9) 43900
10) None of these

Solution

When the item is sold for Rs. 29,050, loss is 17%
So cost price = 29,050 * 100/83 = 35,000

To gain 27% selling price = 127*35,000/100 = 44,450

Correct Option: 5 Best Solution (21)

PRABHAT KUMAR   7 years AGO

selling price of plot={29050*83}/127
44450
option 5

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satish kumar   7 years AGO

83℅=29050
so we get 27℅ profit ,then 127℅=44450

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SAYAN CHATTERJEE   7 years AGO

CP= 29050*100/83
SP with 27 % gain= 29050*100/83*127/100
= 44450
Option 5.

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Mukund Manohar   7 years AGO

When the item is sold for Rs 29050,loss is 17%
So, CP = 29050 * 100/83 = Rs 35000
To get a gain of 27%,
SP = 127*35000/100 = Rs 44450

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Poulami Banik   7 years AGO

X(1-17/100)=29050
X= 35000
35000(1+27/100)
= 44450

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somannagari bhargavi   7 years AGO

the cost price should be 35000 to get a loss of 17%. so to get a gain of 27% the price will be 44450

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G.S.Kantharao   7 years AGO

S.P of the Item =₹.29050
Loss = 17%
C.P of the Item = (29050*100)/(100-13)
= ₹.35000
If it is gain of =27%
Then S.P= 35000*(100+27)/100 = ₹.44450
Hence the right option is 5.

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Shritansh   7 years AGO

Since 83% of x=29050
Therefore x=35000
And 1.27*x= 44450

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Hari Priya   7 years AGO

seller has lossed 17℅. So he selled it for 83℅(100-17). So the original amount is 35000(29050×100/83). Now calculate the gain percent from initial amount. Gain is 27℅. So the price to be sold is 44450(35000×125/100).

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aparna padakanti   7 years AGO

cp=3500
gain =27%
sp=100+27/100×35000=44450

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teja   7 years AGO

83 percent makes 29050 then
127 percent makes 127*29050/83

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MADHUSUDAN DAS   7 years AGO

Solution :

29050 is 83% because he sold on a loss of 17%
we need 27% profit so we have to find 127%

first we will find what will be the 100%

83 = 29050
100=?
(29050*100)/83 = 35000 (our 100%)

100=35000
127=?

(35000*127)/100=44450 (Our Ans)

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pradeep reddy   7 years AGO

Item sold at 29050 owner loss 17 %, means total selling value is 83%

So, if owner get the profit of 27% to sell that item is:

127*29050/83=44450

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Vaibhav Ranpara   7 years AGO

1.
old s.p.=29050
loss 17%
c.p.=29050/.83=35000
2.
c.p.=35000
gain=27%
s.p=35000*1.27=44450

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ramakrishnateja   7 years AGO

From the given conditions,
S.P=29,050, Loss%=17.
As we know that loss=((C.P-S.P)*100)/C.P
17C.P=(C.P-S.P)*100,
83C.P=100S.P
C.P=100*29050/83 C.P=35000.
Now we know C.P=35000.
Hence from the given condition Gain%=27
Gain%=(S.P-C.P)*100/C.P
27=(35000-S.P)*100/35000
S.P=44,450 which satisfies the condition with gain as 27%.

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sanjay   7 years AGO

@83%----->29050 (i.e)83*350=29050
@127%----->44450(i.e)100+27%incr
127*350=44450

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shivakumar saliganti   7 years AGO

100 loss 17%=83
83×350=29050
100+27=127
127×350=44450

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Mayuri Rajendra Karalkar   7 years AGO

Let C.P=x
L=(17/100)x
And S.P+L=C.P
2905+(17/100)x=x
X=C.P=35000
Now 27% gain
New S.P=C.P + (27/100)C.P
S.P=35000+27×350
S.P=35000+9450
S.P=44450

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jhansi angudu   7 years AGO

s.p=29,050
loss=17%
cost prise=100/83*29050
=35000
if gain 27% then
selling prise= 127/100*35000
so s.p=44,450

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Anand Saurabh   7 years AGO

sp->29050;
loss->17/100
then cp = 35000
mf*cp=sp
mf=1.27
then ,
1.27*35000=44450

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Deepika   7 years AGO

S. P= 29050
loss=17%
c. p=29050*100/(100-17) =35000
gain=27%
S. p=35000*(100+27)/(100) = 44450

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07 Jul 2017 Rank of the word

Find Rank of the word THURSDAYS in the dictionary of words formed by the letters of the word THURSDAYS

OPtion

1) 127921
2) 121952
3) 127949
4) 127952
5) 127951
6) 127948
7) 127852
8) 27183
9) 123952
10) None of these

Solution

THURSDAYS
Lets arrange the letters alphabetically = ADHRSSTUY

Words starting with A = 8!/(2!) = 20,160
Words starting with D = 8!/(2!) = 20,160
Words starting with H = 8!/(2!) = 20,160
Words starting with R = 8!/(2!) = 20,160
Words starting with S = 8! = 40320
Words starting with TA = 7!/(2!) = 2520
Words starting with TD = 7!/(2!) = 2520
Words starting with THA = 6!/(2!) = 360
Words starting with THD = 6!/(2!) = 360
Words starting with THR = 6!/(2!) = 360
Words starting with THS = 6! = 720

Words starting with THUA = 5!/(2!) = 60
Words starting with THUD = 5!/(2!) = 60

Words starting with THURA = 4!/(2!) = 12
Words starting with THURD = 4!/(2!) = 12

Words starting with THURSA = 3! = 6

Words starting with THURSDAS = 1

and next word is :
THURSDAYS = 1

Sum of all = 127952

Correct Option: 4 Best Solution (6)

Mukund Manohar   7 years AGO

Rank of the word THURSDAYS
= (6/2!)*8! + (2/2!)*7! + (5/2!)*6! + (2/2!)*5! + (2/2!)*4! + (1/0!)*3! + (0/0!)*2! + (1/0!)*1! + (0/0!)*0! + 1
= 120960 + 5040 + 1800 + 120 + 24 + 6 + 0 + 1 + 0 + 1
= 127952

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Sonu Kumar   7 years AGO

"THURSDAYS"

6 3 7 4 5 2 1 8 5
T H U R S D A Y S
T---6/2!*8!
H---2/2!*7!
U---5/2!*6!
R---2/2!*5!
S---2/2!*4!
D---1/0!*3!
A---0/0!*2!
Y---1/0!*1!
S---0/0!*0!

Find the multiplying value and sum them
Sum=120961+5040+1800+120+24+6+0+1+0
sum=127951+1
Rank of the "THURSDAYS"=sum+1=127952
a correct answer is 4)127952

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G.S.Kantharao   7 years AGO

Arranging alphabetically= A,D,H,R,S,S,T,U,Y(S repeated twice)
Words which started with A=8!/2!=20160
Words with D= 8!/2!=20160
Words with H=8!/2!=20160
Words with R= 8!/2!= 20160
Words with S= (8!/2!)*2=40320
Words. Which starts with TA=7!/2!=2520
With TD=2520
Words which starts with THA=6!/2!=360
With THD= 6!/2=360
With THR= 6!/2!=360
With THS = (6!/2!)*2=720
Words with THUA =5!/2!=60
Words with THUD = 5!/2!=60
Words with THURA= 4!/2!=12
With THURD=4!/2!=12
With THURSA = 3!=6
With THURSDAS=1
Word with THURSDAYS=1
Rank of the Word THURSDAYS=
20160+20160+20160+20160+40320+2520+2520+360+360+360+720+60+60+12+12+6+1+1=129952
Hence the right option is 4

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NABA KISHORE PADHY   7 years AGO

Answer is 127952. THURSDAYS has 9 letters and s repeated twice.

Words with A = 8!/2, words with D = 8!/2, words with H = 8!/2, Words words with R = 8!/2, with S = 8!, with TA = 7!/2, TD = 7!/2, THA = 6!/2, THD = 6!/2,THR = 6!/2, THS =6!,
THUA = 5!/2, THUD = 5!/2 THURA = 4!/2, THURD 4!/2,
THURSA = 3!, THURSDA (SY & YS) = 2. Add all and answer is 127952

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Vahira Bollina   7 years AGO

given word is THURSDAYS
Alphabetical order of given word is A,D,H,R,S,S,T,U,Y
First letter starts with A is 8!/2!=20,160
D is 8!/2!
H is 8!/2!
R is 8!/2!
S is 8!/2!
S is 8!/2!
TA is 7!/2!
TD is 7!/2!
THA is 6!/2!
THD is 6!/2!
THR is 6!/2!
THS is 6!/2!
THS is 6!/2!
THUA is 5!/2!
THUD is 5!/2!
THURA is 4!/2!
THURD is 4!/2!
THURSA is 3!
THURSDAS is 1!
THURSDAYS is 0!

6(8!/2!)+2(7!/2!)+5(6!/2!)+2(5!/2!)+2(4!/2!)+3!+1!+0!=127952

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T.J.Keerthana priya   7 years AGO

t h u r s d a y s
6 3 7 4 5 2 1 8 5
6/2! 2/2! 5/2! 2/2! 2/2! 1/1! 0 1 0
8! 7! 6! 5! 4! 3! 2! 1! 0!
multiply the previous 2 steps and add the results and then u get 127951.......then add 1 then it become 127952

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06 Jul 2017 Speed and Time

A boatman goes 5 km against the current of the stream in 3 hour and goes 4.5 kms along the current in 30 minutes. How long will it take to go 16 km in stationary water?

OPtion

1) 3 hours 33 minutes
2) 3.23 hours
3) 3 hours 30 minutes
4) 3 Hours 0 minutes
5) 3 hours 15 minutes
6) 3.03 hours
7) 3 hours 20 minutes
8) 3 hours 25 minutes
9) 3.5 hours
10)None of these

Solution

Speed (upstream) =5/3 km/hr
Speed (downstream)=4.5/0.5= 9 km/hr

Speed in still water = 1/2 (9+5/3) = 16/3 km/hr

Time taken in stationary water to go 16 KM = 16/16/3 = 3 hr

Option 4)

Correct Option: 4 Best Solution (17)

G.S.Kantharao   7 years AGO

Up strem relative speed=(x-y)kmph
Time taken=3hrs
Distance = 3(X-Y)= 5
3X-3Y=5
Downward Relative Speed= (X+Y)kmph
Time taken 1/2hr
(X+Y)*1/2= 4.5
(X+Y)=9
Simplyfing 6X=32
X=16/3
In still water time taken to travel 16km= 16/(16/3)=3hrs. Hence the right option is 4.👍

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SAYAN CHATTERJEE   7 years AGO

let, speed at stationary water= x and speed of boat= y
so, 5/(x-y)= 3,
4.5/(x+y)=0.5
on solving, x=16/3
so, time reqd to travel a distance of 16 km = 16/(16/3)
= 3 hours.
Option 4.

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tumati koushik   7 years AGO

Stream velocity =s
Boat velocity =b
S+b=4.5x2=9
B-S=5/3
B=16/3
So 16 km in 3 hours

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AYAN PAUL   7 years AGO

Speed of boat against the current is = 5/3 Km/hr
Speed of boat with the current is = 9 Km/hr
So speed of boat in stationary water will be = 16/3 Km / hr
So the time required to travel 16 km will be = 16*3/16 = 3 hr.

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ganesh chemanchula   7 years AGO

Sped in Upstream is 5/3
Speed in downstream (4.5/(1/2))
Speed in still water is 1/2(speed in upstream + speed in downstream)=1/2(32/3)=(32/6)
Time take to cover 16 kms in still water is 16/(32/6)=96/32=3 hours
So option 4.

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Prerna   7 years AGO

If B is speed of boat in stationary water and C is speed of current, then
B+C= 4.5*2= 9 km/hr
B-C= 5/3
2B= 32/3 km/hr
B=16/3 km/hr
so time taken by boat to travel 16 km in stationary water = 3 hrs

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Mukund Manohar   7 years AGO

Speed Upstream = 5/3 km/h
Speed Downstream = 4.5/(30/60) = 9 km/hr
Speed in still water = 1/2(5/3 + 9) = 16/3 km/hr
Time taken to travel 16 km in still water = 16/(16/3) = 3 hrs

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Tavva Deepthi   7 years AGO

upstream =5/3=1.666666667km/hr
downstream=4.5/(30/60)=9km/hr
speed in still water =1/2*(1.666666667)=5.333333334km/hr
time taken on stationary water to go 16km=16/5.333333334=3hours0minutes

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Saptarsy Chakraborty   7 years AGO

Speed of boat-speed of stream=5/3 km/hr ----(1)
Speed of Boat+Speed of stream = 4.5/30 km/min
= 4.5/0.5 km/hr
= 9 km/hr. -------(2)
(2) - (1) OR (2) minus (1),
2*speed of boat=32/3. Therefore Sp of boat= 16/3 km/hr.

So, Time taken by boat in still water= dist. /speed
=16/(16/3)
=3 hours.

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Pallavolu vaasavi   7 years AGO

v-u=5/180
v-u=4.5/30
by solving the above equations we get v=4/45
v=d/t
4/45=16/t
therefore t=180min
t=3hrs 0min

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Shoieb   7 years AGO

b-s=5/3
b+s=9
we get b=16/3
for 16km it will take 16÷16/3 = 3

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Gnana Shankar   7 years AGO

The speed of the batman is 16/3 kmph and the speed of current is 11/3 kmph. So in a stationary water he goes 16 km in 3 hours without the help of current speed but only by his speed.

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Mathangi   7 years AGO

Going against the stream means upstream. so the upstream speed is (5/3) km/hr. And going along the stream means downstream, and the downstream speed is (4.5/(1/2)), i.e 4.5*2=9 km/hr. (30 minutes is converted into 1/2 hours). now speed in still water is (upstream+downstream speeds)/2. Hence ((9+(5/3))/2)= 16/3 km/hr. The distance is 16 km. So time is distance/speed which will be equal to 16/(16/3)= 3 hours.

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Sri Harshitha   7 years AGO

upward stream
for 5km he takes 3 hours(against so upward stream)
for 1 hour 1.6666 km
downard stream
(4.5*60)/30=9
speed in still water=1/2*(9+1.6666)=5.3333
required time=16/5.3333=3 hours 0 minutes

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saima haque   7 years AGO

Speed in stationary water=(5/3 +4.5×2/3)/2=32/6.
Now time taken for 16km =16×6/32=3 hr

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palak Jain   7 years AGO

speed of downstream a=4.5*60/30=2km/hr
speed of upstream b=5/3 km/hr
speed of boat u=(a+b)/2=32/6 km/hr
time=16*6/32=3 hr

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Sirra surresh   7 years AGO

5000/180=250/9 so 250mt in 9 min in upstream.1350 Mt in 9min I'm down stream so the average is800 Mt in9min still water
So 16000mt in180 min

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